A) There was no change in the number of students on honor roll from one year to the next. This is noticeable because 200/1000 = .2 just as 20%/100% = .2 or 20/100 = .2. So there never was a change!
Answer:The graph below represents which system of inequalities? graph of two infinite lines that intersect at a point. One line is solid and goes through the points negative 3, 0, negative 4, negative 1 and is shaded in below the line. The other line is solid, and goes through the points 1, 1, 2, negative 1 and is shaded in below the line
Step-by-step explanation:y ≤ −2x + 3 y ≤ x + 3 y ≥ −2x + 3 y ≥ x + 3 y ≤ −3x + 2 y ≤ −x + 2 y > −2x + 3 y > x + 3
Y = mx + b
M= your slope or rise over run
B = your y-intercept
For example if the rise was 5 and the run is 6, the equation would say
y = 5/6 + b
The / being your fraction bar
The y-intercept is where your line crosses the y-axis
So say that the line crosses the y-axis at 10
y = 5/6 + 10
That about sums it all up!
The amount of pounds of vegetable needed in fractions to make the stew exactly 10 pounds is 3 3 / 8 pounds
<h3>How to solve fractions?</h3>
The amount of pounds of vegetable needed to make the stew exactly 10 pounds can be calculated as follows:
potatoes weight = 2 7 / 8 pounds = 23 / 8 pounds
green beans weight = 1 1 / 4 = 5 / 4 pounds
pepper weight = 2 1 / 2 = 5 / 2 pounds
Therefore,
weight needed = 10 - 23 / 8 - 5 / 4 - 5 / 2
weight needed = 80 - 23 - 10 - 20 / 8
weight needed = 80 - 53 / 8
weight needed = 27 / 8
weight needed in fractions to make the stew exactly 10 pounds = 3 3 / 8 pounds
learn more on fractions here: brainly.com/question/27894307
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Answer:
The turns of a graph is represented by the number of maximum or minimum that the function has.
If we differenciate f(x) we get:
f'(x)=4x^3+6x
f'(x)=2x(2x^2 + 3)
Therefore f'(x) =0, when x=0. Given that negative roots are not defined.
Therefore, the number of turns will be given by the number of solutions of f'(x) which is 1.
Attached you find the graph of the function which confirms the number of turns.
If the function had other solutions, the maximum number of turns it could have is 3! because f'(x) is a third degree polynomial, therefore it can't have more than 3 solutions!
