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3 years ago

Give a example of a multi-step equation for each of the following solution

Mathematics

1 answer:

ikadub [295]3 years ago

3 0

Here is the example.

Multi-step equation means before start solving equations, you need to isolate the variable terms and constant terms, then you have to combine the like terms.

Finally, you can solve the equation. This involves more than two steps.

Examples:

1) 2x + 3x + 5 = 20

Step 1: Isolate the variable terms and constants.

Subtract 5 on both sides, we get

2x + 3x + 5 - 5 = 20 -5

2x + 3x = 15

Step 2: Combine the like terms.

5x = 15

Step 3: Divide both sides by 5.

5x/5 = 15/5

x = 3.

2) 2(3x + 2) = 3(x - 1) + 4

Step 1: Use the distributive property and expand the given equation.

6x + 4 = 3x -3 + 4

Step 2: Isolate the variable terms and constants

Subtract 3x from both sides, we get

6x - 3x + 4 = 3x - 3x -3 + 4

3x + 4 = -3 + 4

Step 3: Simplify it.

3x + 4 = 1

Step 4: Subtract 4 from both sides.

3x + 4 - 4 = 1 - 4

3x = -3

Step 5: Divide both sides by 3.

3x/3 = -3/3

x = -1.

Hope this will help you. :)

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Consider that x = 5 and y = 7. Which statement is true about x + y? A) The sum of x and y is a rational number. B) The sum of x

gayaneshka [121]

Answer:

The sum of x and y is a rational number

Step-by-step explanation:

X+Y or 5+7=12

A rational number is any number that can be divided without going on and on forever.

5 0

3 years ago

Read 2 more answers

Suppose a shipment of 120 electronic components contains 3 defective components. to determine whether the shipment should be ac

Likurg_2 [28]

For this problem, the most accurate is to use combinations

Because the order in which it was selected in the components does not matter to us, we use combinations

Then the combinations are $nC_r = \frac{ n! }{r! (n-r)!}$

n represents the amount of things you can choose and choose r from them

You need the probability that the 3 selected components at least one are defective.

That is the same as:

(1 - probability that no component of the selection is defective).

The probability that none of the 3 selected components are defective is:

$P = \frac{_{117}C_3}{_{120}C_3}$

Where $_{117}C_3$ is the number of ways to select 3 non-defective components from 117 non-defective components and $_{120}C_3$ is the number of ways to select 3 components from 120.