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inysia [295]
3 years ago
13

What is the area of the triangle.

Mathematics
1 answer:
blagie [28]3 years ago
3 0

Answer:

36mm

Step-by-step explanation:

Ok so, here is what you do the 10mm and the 4mm you subtract them to get 6 then you will use 6 for the base of the triangle since, when we subtracted we got the rest for the bottom base of the triangle. Then we do 6 times 12 and we get 72. We divide 72 divided by 2 and get 36 and that is your answer 36mm.

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In the best 30 years for the housing market (1976-2005), real price appreciation averaged 2.2% per year. In the worst 30 years for housing (1895-1924), real price appreciation averaged -2.0% per year.

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ALGEBRAIC PROOF!!!! PLS HELP!!! The area of a rectangular blanket is 20 square feet. The blanket's length is (2x + 1) ft and the
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Answer:

Length: 5 ft; width: 4 ft.

Step-by-step explanation:

A = LW     formula for area of rectangle

(2x + 1)(2x) = 20      substitute length, width, and area into formula

4x² + 2x - 20 = 0      use the distributive property to multiply out left side

2x² + x - 10 = 0         divide both sides of equation by 2

(2x + 5)(x - 2) = 0        factor out trinomial

2x + 5 = 0  or  x - 2 = 0        use zero product rule to solve for x

2x = -5  or x = 2       subtract 5 from both sides; add 2 to both sides

x = -5/2  or  x = 2

We discard x = -5/2 since it would give negative length and width, and the length and width cannot be negative.

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7 0
3 years ago
Find the value of the variable.
nalin [4]

Answer:

The variable, y is 11°

Step-by-step explanation:

The given parameters are;

in triangle ΔABC;          {}              in triangle ΔFGH;

Segment \overline {AB} = 14         {}               Segment \overline {FG} = 14

Segment \overline {BC} = 27         {}              Segment \overline {GH} = 19

Segment \overline {AC} = 19         {}               Segment \overline {FH} = 2·y + 5

∡A = 32°                       {}                ∡G = 32°

∡A = ∠BAC which is the angle formed by segments \overline {AB} = 14 and \overline {AC} = 19

Therefore, segment \overline {BC} = 27, is the segment opposite to ∡A = 32°

Similarly, ∡G = ∠FGH which is the angle formed by segments \overline {FG} = 14 and \overline {GH} = 19

Therefore, segment \overline {FH} = 2·y + 5, is the segment opposite to ∡A = 32° and triangle ΔABC ≅ ΔFGH by Side-Angle-Side congruency rule which gives;

\overline {FH} ≅ \overline {BC} by Congruent Parts of Congruent Triangles are Congruent (CPCTC)

∴ \overline {FH} = \overline {BC} = 27° y definition of congruency

\overline {FH} = 2·y + 5 = 27° by transitive property

∴ 2·y + 5 = 27°

2·y = 27° - 5° = 22°

y = 22°/2 = 11°

The variable, y = 11°

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