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3 years ago

HELP HELP HELP I AM TIMED PLZ PLZ HELP!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!

Mathematics

2 answers:

kenny6666 [7]3 years ago

8 0

Answer:64

Step-by-step explanation:

AleksAgata [21]3 years ago

4 0

Answer:

I believe its 64 I am so sorry if its wrong.

Step-by-step explanation:

You might be interested in

Evaluate f(x+3) when f(x)=-x^2-2x+2

ziro4ka [17]

Answer:

f(x + 3) = -x² - 8x - 13

General Formulas and Concepts:

Pre-Algebra

Order of Operations: BPEMDAS

Brackets
Parenthesis
Exponents
Multiplication
Division
Addition
Subtraction

Left to Right

Algebra I

Function Notation
Expanding
Terms/Coefficients/Degrees

Step-by-step explanation:

Step 1: Define

f(x) = -x² - 2x + 2

f(x + 3) is x = x + 3

Step 2: Find

Substitute in x: f(x + 3) = -(x + 3)² - 2(x + 3) + 2
Expand: f(x + 3) = -(x² + 6x + 9) - 2x - 6 + 2
Distribute -1: f(x + 3) = -x² - 6x - 9 - 2x - 6 + 2
Combine like terms: f(x + 3) = -x² - 8x - 13

3 0

3 years ago

Y=(1/2)^x +2. What is the horizontal asymptote of this function?

professor190 [17]

$\lim_{x\to -\infty} \left(\frac{1}{2}\right)^x+2=\infty+2=\infty\\
\lim_{x\to \infty} \left(\frac{1}{2}\right)^x+2=0+2=2\\$

There is one-sided horizontal asymptote $y=2$

6 0

4 years ago

How many times does 4 go into 78

Bess [88]

You would do 78/4 which equals 19.5. Hope this helps!

4 0

3 years ago

Read 2 more answers

What is the 56th term of the sequence below? -29, -25, -21, -17, . . .

dimulka [17.4K]

The 56th term in the sequence is 195

6 0

3 years ago

Read 2 more answers

Miriam is picking out some movies to rent, and she is primarily interested in comedies and foreign films. She has narrowed down

Keith_Richards [23]

Answer:

There are 795 combinations.

Step-by-step explanation:

The number of ways or combinations in which we can select k element from a group of n elements is given by:

$nCk=\frac{n!}{k!(n-k)!}$

So, if Miriam want to choose 3 movies with at least two comedies, she have two options: Choose 2 comedies and 1 foreign film or choose 3 comedies.

Then, the number of combinations for every case are:

1. Choose 2 Comedies from the 10 and choose 1 foreign film from 15. This is calculated as:

$10C2*15C1=\frac{10!}{2!(10-8)!}*\frac{15}{1!(15-14)!}$

$10C2*15C1=675$

2. Choose 3 Comedies from the 10. This is calculated as:

$10C3=\frac{10!}{3!(10-3)!}=120$

Therefore, there are 795 combinations and it is calculated as:

675 + 120 = 795

8 0

3 years ago