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3 years ago

Y = −2 4x − 3y = 18 solved by substitution please show work so i can understand :)

Mathematics

2 answers:

ycow [4]3 years ago

5 0

Answer:

Step-by-step explanation:

y = -2

4x - 3y = 18

4x - 3(-2) = 18

4x + 6 = 18

4x = 12

x = 3

(3, -2)

vesna_86 [32]3 years ago

5 0

Answer:

I love algebra

The ans is in the picture with the steps how i got it

(hope this helps can i plz have brainlist :D hehe)

Step-by-step explanation:

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Which term of the Ap: 9,8,13,18.......is 79?<br><br>Please don't post invalid answer..!!

GalinKa [24]

$a {}^{n} = 79$

$n = ?$

$a = 3$

$79 = 3 + (n - 1) \times 5$

$76 = 5n - 5 \\ 81 = 5n \\ n = 16.2$

16.2 is the answer

4 0

2 years ago

How do I slove this eqaution, and whats the answer?<br> -3(n+6)+10=-9

Sauron [17]

Answer:

$n = \frac{1}{3}$

Step-by-step explanation:

Apply the distributed property, so it now looks like this: -3n + -18 + 10 = -9
Combine like terms: -3n + -8 = -9
Simplify: -3n - 8 = -9
Add 8 to each side, so it now looks like this: -3n = -1
Divide each side by -3 to cancel out the -3 next to n. It should now look like this: n = 1/3

I hope this helps!

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3 years ago

Which equation can replace 3x + 5y = 59 in the original system and still produce the same solution?

mafiozo [28]

Answer:

13x = 39

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5 0

1 year ago

Expand (2x+2)^6<br> How would you find the answer using the binomial theorem?

Yanka [14]

Answer:

Step-by-step explanation:

$\displaystyle\\\sum\limits _{k=0}^n\frac{n!}{k!*(n-k)!}a^{n-k}b^k .\\\\k=0\\\frac{n!}{0!*(n-0)!}a^{n-0}b^0=C_n^0a^n*1=C_n^0a^n.\\\\ k=1\\\frac{n!}{1!*(n-1)!} a^{n-1}b^1=C_n^1a^{n-1}b^1.\\\\k=2\\\frac{n!}{2!*(n-2)!} a^{n-2}b^2=C_n^2a^{n-2}b^2.\\\\k=n\\\frac{n!}{n!*(n-n)!} a^{n-n}b^n=C_n^na^0b^n=C_n^nb^n.\\\\C_n^0a^n+C_n^1a^{n-1}b^1+C_n^2a^{n-2}b^2+...+C_n^nb^n=(a+b)^n.$

$\displaystyle\\(2x+2)^6=\frac{6!}{(6-0)!*0!} (2x)^62^0+\frac{6!}{(6-1)!*1!} (2x)^{6-1}2^1+\frac{6!}{(6-2)!*2!}(2x)^{6-2}2^2+\\\\ +\frac{6!}{(6-3)!*3!} (2a)^{6-3}2^3+\frac{6!}{(6-4)*4!} (2x)^{6-4}b^4+\frac{6!}{(6-5)!*5!}(2x)^{6-5} b^5+\frac{6!}{(6-6)!*6!}(2x)^{6-6}b^6. \\\\$

$(2x+2)^6=\frac{6!}{6!*1} 2^6*x^6*1+\frac{5!*6}{5!*1}2^5*x^5*2+\\\\+\frac{4!*5*6}{4!*1*2}2^4*x^4*2^2+ \frac{3!*4*5*6}{3!*1*2*3} 2^3*x^3*2^3+\frac{4!*5*6}{2!*4!}2^2*x^2*2^4+\\\\+\frac{5!*6}{1!*5!} 2^1*x^1*2^5+\frac{6!}{0!*6!} x^02^6\\\\(2x+2)^6=64x^6+384x^5+960x^4+1280x^3+960x^2+384x+64.$

8 0

1 year ago

It costs $5.15 to rent a kayak for 1 hour at a local state park. The price per hour stays the same for up to 5 hours of rental.

iren [92.7K]

5.15 x 5 = 25.75

25.75 + 3.75 = 29.5

So your answer is $29.50

Hope it helps! :D

6 0

3 years ago