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Julli [10]
2 years ago
10

PLEASE PLEASE solve step by step !!!!!!! I will mark Brianliest correct answer !!!

Mathematics
1 answer:
gulaghasi [49]2 years ago
3 0

Answer:

m<3 = 70 and m<4 = 110

Step-by-step explanation:

<3 and <4 are vertical angles so they add up to 180

(3y + 7) + (5y + 5) = 180

(3y + 5y) + (7 + 5) = 180

8y + 12 = 180

-12 -12

8y = 168

/8 /8

y = 21

find the angle measures:

3(21) + 7

63 + 7

70

5(21) + 5

105 + 5

110

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Answer:

The work is in the explanation.

Step-by-step explanation:

The sine addition identity is:

\sin(a+b)=\sin(a)\cos(b)+\cos(a)\sin(b).

The sine difference identity is:

\sin(a-b)=\sin(a)\cos(b)-\cos(a)\sin(a).

The cosine addition identity is:

\cos(a+b)=\cos(a)\cos(b)-\sin(a)\sin(b).

The cosine difference identity is:

\cos(a-b)=\cos(a)\cos(b)+\sin(a)\sin(b).

We need to find a way to put some or all of these together to get:

\sin(a)\cos(b)=\frac{\sin(a+b)+\sin(a-b)}{2}.

So I do notice on the right hand side the \sin(a+b) and the \sin(a-b).

Let's start there then.

There is a plus sign in between them so let's add those together:

\sin(a+b)+\sin(a-b)

=[\sin(a+b)]+[\sin(a-b)]

=[\sin(a)\cos(b)+\cos(a)\sin(b)]+[\sin(a)\cos(b)-\cos(a)\sin(b)]

There are two pairs of like terms. I will gather them together so you can see it more clearly:

=[\sin(a)\cos(b)+\sin(a)\cos(b)]+[\cos(a)\sin(b)-\cos(a)\sin(b)]

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So this implies:

\sin(a+b)+\sin(a-b)=2\sin(a)\cos(b)

Divide both sides by 2:

\frac{\sin(a+b)+\sin(a-b)}{2}=\sin(a)\cos(b)

By the symmetric property we can write:

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3 years ago
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3 years ago
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Answer:

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