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3 years ago

The quotient of the cube root of x and nine

Mathematics

1 answer:

miss Akunina [59]3 years ago

8 0

Answer:

$\frac{ \sqrt[3]{x} }{9}$

Quotient means the answer after dividing two numbers.

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In a circle of radius 60 inches, a central angle of 35° will intersect the circle forming an arc of length

Dmitriy789 [7]

$\bf \textit{arc's length}\\\\
s=\cfrac{\theta \pi r}{180}~~
\begin{cases}
r=radius\\
\theta =angle~in\\
\qquad degrees\\
------\\
r=60\\
\theta =35
\end{cases}\implies s=\cfrac{(35)(\pi )(60)}{180}\implies s=\cfrac{35\pi }{3}$

5 0

3 years ago

Read 2 more answers

Maria has five orange, seven green, three red, and nine blue toothpicks in a bag. If Maria randomly selects one toothpick out of

Kryger [21]

Well first you have to find how many toothpicks in the bag so O+G+R+B=24. So 24 toothpicks in a bag. And R+B=12 so you can simplify and do 1 of the following

1.12 2. 6 3. 3 4. 2 5. 1
--- -- -- -- ---
24 12 6 4 2

Hope this helps!!

3 0

3 years ago

A piece of wire 19 m long is cut into two pieces. One piece is bent into a square and the other is bent into an equilateral tria

mr Goodwill [35]

Answer: 8.26 m

Step-by-step explanation:

$Let s be the length of the wire used for the square. \\Let $t$ be the length of the wire used for the triangle. \\Let $A_{S}$ be the area of the square. \\Let ${A}_{T}}$ be the area of the triangle. \\One side of the square is $\frac{s}{4}$ \\Therefore,we know that,$$A_{S}=\left(\frac{s}{4}\right)^{2}=\frac{s^{2}}{16}$

$The formula for the area of an equilateral triangle is, $A=\frac{\sqrt{3}}{4} a^{2}$ where $a$ is the length of one side,And one side of our triangle is $\frac{t}{3}$So,We know that,$$A_{T}=\frac{\sqrt{3}}{4}\left(\frac{t}{3}\right)^{2}$$We have to find the value of "s" such that,$\mathrm{s}+\mathrm{t}=19$ hence, $\mathrm{t}=19-\mathrm{s}$And$$A_{S}+A_{T}=A_{S+T}$

$$$Therefore,$$\begin{aligned}&A_{T}=\frac{\sqrt{3}}{4}\left(\frac{(19-s)}{3}\right)^{2}=\frac{\sqrt{3}(19-s)^{2}}{36} \\&A_{T+S}=\frac{s^{2}}{16}+\frac{\sqrt{3}(19-s)^{2}}{36}\end{aligned}$

$Differentiating the above equation with respect to s we get,$$A^{\prime}{ }_{T+S}=\frac{s}{8}-\frac{\sqrt{3}(19-s)}{18}$$Now we solve $A_{S+T}^{\prime}=0$$$\begin{aligned}&\Rightarrow \frac{s}{8}-\frac{\sqrt{3}(19-s)}{18}=0 \\&\Rightarrow \frac{s}{8}=\frac{\sqrt{3}(19-s)}{18}\end{aligned}$$Cross multiply,$$\begin{aligned}&18 s=8 \sqrt{3}(19-s) \\&18 s=152 \sqrt{3}-8 \sqrt{3} s \\&(18+8 \sqrt{3}) s=152 \sqrt{3} \\&s=\frac{152 \sqrt{3}}{(18+8 \sqrt{3})} \approx 8.26\end{aligned}$

$The domain of $s$ is $[0,19]$.So the endpoints are 0 and 19$$\begin{aligned}&A_{T+S}(0)=\frac{0^{2}}{16}+\frac{\sqrt{3}(19-0)^{2}}{36} \approx 17.36 \\&A_{T+S}(8.26)=\frac{8.26^{2}}{16}+\frac{\sqrt{3}(19-8.26)^{2}}{36} \approx 9.81 \\&A_{T+S}(19)=\frac{19^{2}}{16}+\frac{\sqrt{3}(19-19)^{2}}{36}=22.56\end{aligned}$

$$$Therefore, for the minimum area, $8.26 \mathrm{~m}$ should be used for the square$

8 0

2 years ago

what types of problems can be solved using the greatest common factor what types of problems can be solved using the last common

jonny [76]

Answer:

The greatest common factor is the biggest factor that divides two different numbers. For example, the greatest common factor of 6 and 8 is 2. The least common multiple is the smallest number that two numbers share as a multiple. For example, 12 is a the lowest common multiple of 3 and 4.

Step-by-step explanation:

3 0

4 years ago

What is the absolute value of Point B labelled on the number line? A number line with point A at coordinate negative 2.2, point

bulgar [2K]

Answer:

The absolute value of point B on the number line is 2.2.

Step-by-step explanation:

A number line is given with point A at coordinate negative 2.2, point B at coordinate negative 1.6, and point C at coordinate 1.2.

So, on the number line, all the points having negative value are on the left side of zero.

Position of the point A is -2.2,

Position of the point B is -1.6,

Position of the point C is -1.2.

The absolute value of any point on the number line is the distance of that point from zero.

So, the absolute value of point B on the number line is the distance of point B from zero which is |-2,2|=2.2.

7 0

3 years ago