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Brrunno [24]
3 years ago
9

Can someone tell me the right answer

Mathematics
1 answer:
butalik [34]3 years ago
5 0

Answer:

<h2>Sorry I couldn't find it.</h2>

Step-by-step explanation:

<h3>:((((((((((((((</h3>
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PLEASEEEEEE HELP ME !!!!
vfiekz [6]

Answer:

A  and b

Step-by-step explanation:

Be has an arrow towards the end signaling it moving outward just like GH

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2 years ago
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If the gradient of the tangent to
Marizza181 [45]

Answer:

Point A(9, 3)

General Formulas and Concepts:

<u>Pre-Algebra</u>  

Order of Operations: BPEMDAS  

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right  

Equality Properties  

  • Multiplication Property of Equality
  • Division Property of Equality
  • Addition Property of Equality
  • Subtraction Property of Equality

<u>Algebra I</u>  

  • Coordinates (x, y)
  • Functions
  • Function Notation
  • Terms/Coefficients
  • Anything to the 0th power is 1
  • Exponential Rule [Rewrite]:                                                                              \displaystyle b^{-m} = \frac{1}{b^m}
  • Exponential Rule [Root Rewrite]:                                                                     \displaystyle \sqrt[n]{x} = x^{\frac{1}{n}}  

<u>Calculus</u>  

Derivatives  

Derivative Notation  

Derivative of a constant is 0  

Basic Power Rule:  

  • f(x) = cxⁿ
  • f’(x) = c·nxⁿ⁻¹

Derivative Rule [Chain Rule]:                                                                                    \displaystyle \frac{d}{dx}[f(g(x))] =f'(g(x)) \cdot g'(x)

Step-by-step explanation:

<u>Step 1: Define</u>

<em>Identify</em>

<em />\displaystyle y = \sqrt{x}<em />

<em />\displaystyle y' = \frac{1}{6}<em />

<em />

<u>Step 2: Differentiate</u>

  1. [Function] Rewrite [Exponential Rule - Root Rewrite]:                                   \displaystyle y = x^{\frac{1}{2}}
  2. Basic Power Rule:                                                                                             \displaystyle y' = \frac{1}{2}x^{\frac{1}{2} - 1}
  3. Simplify:                                                                                                             \displaystyle y' = \frac{1}{2}x^{-\frac{1}{2}}
  4. [Derivative] Rewrite [Exponential Rule - Rewrite]:                                          \displaystyle y' = \frac{1}{2x^{\frac{1}{2}}}
  5. [Derivative] Rewrite [Exponential Rule - Root Rewrite]:                                 \displaystyle y' = \frac{1}{2\sqrt{x}}

<u>Step 3: Solve</u>

<em>Find coordinates of A.</em>

<em />

<em>x-coordinate</em>

  1. Substitute in <em>y'</em> [Derivative]:                                                                             \displaystyle \frac{1}{6} = \frac{1}{2\sqrt{x}}
  2. [Multiplication Property of Equality] Multiply 2 on both sides:                      \displaystyle \frac{1}{3} = \frac{1}{\sqrt{x}}
  3. [Multiplication Property of Equality] Cross-multiply:                                      \displaystyle \sqrt{x} = 3
  4. [Equality Property] Square both sides:                                                           \displaystyle x = 9

<em>y-coordinate</em>

  1. Substitute in <em>x</em> [Function]:                                                                                \displaystyle y = \sqrt{9}
  2. [√Radical] Evaluate:                                                                                         \displaystyle y = 3

∴ Coordinates of A is (9, 3).

Topic: AP Calculus AB/BC (Calculus I/II)

Unit: Derivatives

Book: College Calculus 10e

7 0
3 years ago
The figure, polygon ABCD is dilated by a factor of 2 to produce A B C D with the origin as the center of dilation
cestrela7 [59]

In the polygon ABCD, the production of point A' and point D' is (-2,-2)  and (4,-2) respectively.

<h3>What is the transformation rule?</h3>

In coordinate planes, the rule of transformation involves interchanging the x and y values on the plane such that:

\mathbf{(x,y) \to  (k_x, k_y)}

where;

  • k = scale factor

From the given information:

  • The scale factor = 2
  • the origin as a center of dilation for image vertices = (0, 0)

Now, using the coordinate vertices:

  • A = (-1, -1)
  • D = (2, -1)

The corresponding coordinate of the image vertices is as follows:

A(-1,-1) → A'(2 × (-1), 2 × (-1))

A' = (-2,-2)

D(2,-1) → A'(2 × (2), 2 × (-1))

D' = (4,-2)

Learn more about the transformation rule in coordinate planes here:

brainly.com/question/4251601

#SPJ1

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the anwser to this queation is D

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