The answer of this problem is A because 3 times 21 is 63 and then you plus 1
which is 64
Please note that your x^3/4 is ambiguous. Did you mean (x^3) divided by 4
or did you mean x to the power (3/4)? I will assume you meant the first, not the second. Please use the "^" symbol to denote exponentiation.
If we have a function f(x) and its derivative f'(x), and a particular x value (c) at which to begin, then the linearization of the function f(x) is
f(x) approx. equal to [f '(c)]x + f(c)].
Here a = c = 81.
Thus, the linearization of the given function at a = c = 81 is
f(x) (approx. equal to) 3(81^2)/4 + [81^3]/4
Note that f '(c) is the slope of the line and is equal to (3/4)(81^2), and f(c) is the function value at x=c, or (81^3)/4.
What is the linearization of f(x) = (x^3)/4, if c = a = 81?
It will be f(x) (approx. equal to)
If you roll a fair 6-sided die you can get 1, 2, 3, 4, 5 or 6. In total there are 6 possibilities for the outcomes. The theoretical probability to roll each number of 6 possible is the same and equal to 1/6.
If you roll a fair 6-sided die 600 times, you can expect that near 1/6 of these attempts will get you 3's. Then you expect about 600·1/6=100 3’s (you can't suppose to get exactly 100 3's, because the experimental probability may differ from theoretical).
Answer: correct choice is A.
To solve, the first step is to find the LCM (least common denominator). In this scenario, it's ten.
6 5/10 - 2 3/10
From here, do the math. It's easy this time, what's 5 - 3? Two.
Now, subtract two from six. (four)
4 and 2/10
4 and 1/5
There! :)
Answer:
negative numbers can't have a square root it would have to be imaginary
Step-by-step explanation:
