Answer:
Hello,
Answer C: -40
Step-by-step explanation:
I don't get what they mean by "Coach Green could possibly have
1 answer:
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<h2><u>Answer:</u></h2><h2><u></u>
<u></u></h2><h2><u></u></h2><h2><u>Solution Steps:</u></h2>
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<h3>1.) Combine x and 3x:</h3>
<em> - We combine the </em><em> variables because to get to the end sum of the equation, there can only be 1 variable. So to get the 1, you combine like terms. </em>
<em />
<h3>2.) Add 19 to both sides:</h3>Cancels Out
- <em></em>
<em></em>
<em> - We do this to get 1 number left over. To do this you do the opposite of what you see. In this case we have a negative 19, so you add 19 on each side of the equals. </em>
<em />
<h3>3.) Divide both sides by 4:</h3>÷
÷
<em> - We do this to get x alone. To do this you do the opposite of what you see. In this case we have </em><em> which is multiplying, so you divide by 4 on each side. </em>
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So your answer is .
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Answer:
A non-equilateral rhombus.
Step-by-step explanation:
We can solve this graphically.
We start with square:
ABCD
with:
A = (11, - 7)
B = (9, - 4)
C = (11, - 1)
D = (13, - 4)
Only with the vertices, we can see that ABCD is equilateral, as the length of each side is:
AB = √( (11 - 9)^2 + (-7 -(-4))^2) = √( (2)^2 + (3)^2) = √(4 + 9) = √13
BC = √( (11 - 9)^2 + (-1 -(-4))^2) = √13
CD = √( (11 - 13)^2 + (-1 -(-4))^2) = √13
DA = √( (11 - 13)^2 + (-7 -(-4))^2) = √13
And we change C by C' = (11, 1)
In the image you can see the 5 points and the figure that they make:
The figure ABCD is a rhombus, and ABC'D is also a rhombus, the only difference between the figures is that ABCD is equilateral while ABC'D is not equilateral.
