3 years ago

A line with a slope of 3 passes through the point (-1, 2).

Mathematics

1 answer:

Rom4ik [11]3 years ago

8 0

Answer:

y - 2 = 3(x + 1)

y - 2 = 3x + 3

y = 3x + 5

Step-by-step explanation:

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When y = 35,x = 2.5. If the value of y varies directly with x what is the value of y when the value of xis 3.25

leonid [27]

Answer:

The value of y would be 45.5

Step-by-step explanation:

To solve this problem, start with the base form of direct variation.

y = kx

Now we can use our original values to model the equation and find k.

35 = k(2.5)

14 = k

Now we can model the equation as:

y = 14x

Now to find y, when x = 3.25, simply put 3.25 into the equation.

y = 14(3.25)

y = 45.5

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4 years ago

Find the equation of the line passing through the point (8, -4) and slope -4.

ehidna [41]

Answer:

y+4x=36

Step-by-step explanation:

the answer isn't in the choice

3 0

3 years ago

In Joe's fish tank, there are 5 goldfish and 9 snails. How does the ratio 9:14 describe Joe's fish tank?

Natalija [7]

The answer is C, number of snails to the total number of animals

4 0

2 years ago

There were 40 fingers total on the number of gloves Mrs. Edwards knitted. How many gloves did Mrs.Edward knit.

GarryVolchara [31]

40 ÷10 = 4

Mrs Edward knitted 4 pairs of gloves.

7 0

4 years ago

Read 2 more answers

1 point) Are the functions f,g, and h given below linearly independent? f(x)=e3x+cos(5x), g(x)=e3x−cos(5x), h(x)=cos(5x). If the

Fynjy0 [20]

Answer:

Functions are linearly dependent (are not linearly independent.)

Step-by-step explanation:

Remember that two functions f(x), g(x) and h(x) are said linearly independent on an interval I if the <em>only solution</em> to the equation

$\alpha f(x)+\beta g(x)+\omega h(x)=0, \ \text{for all } x\in I$

is the trivial one: α = 0, β = 0, ω = 0. If they are not linearly independent, they are called linearly dependent.

Now, let f(x), g(x) and h(x) be the functions:

$f(x)=e^{3x}+\cos(5x),$

$g(x)=e^{3x}-\cos(5x),$

$h(x)=\cos(5x).$

Then, letting α = 1, β= -1 and ω = -2, we see that:

$\alpha f(x)+\beta g(x)+ \omega h(x)=e^{3x}+\cos(5x)-e^{3x}+\cos(5x)+2\cos(5x)=0.$

Hence, the functions f(x), g(x) and h(x) are not linearly independent, or equivalently, are linearly dependent.

8 0

3 years ago