MN is the mid-line of a trapezoid HJLK.<span>
The length of the mid-line of a trapezoid is half of the sum of the lengths of its bases </span>⇒
<span>
(KL + HJ)/2 = MN
(KL + 45)/2 = 28
KL + 45 = 28 * 2
KL + 45 = 56
KL = 56 - 45
KL = 11
</span><span>
</span>
(x+8) - 13 is the answer using x as “number”
Answer:
A = 26
Step-by-step explanation:
sum of students = classA + classB + classC
let's say classA = A, classB = B, and classC = C
A + B + C = 66
class A has five more students than class B, so A = 5 more than B so A = 5+B
class C has 2 less students than class B, so C = 2 less than class B = B -2, so C = B-2
A + B + C = 66
A = 5+B
C = B-2
substitute 5+B for A and B-2 for C in the first equation to limit this to one variable (B)
(5+B) + B + (B-2) = 66
3B + 3 = 66
subtract 3 from both sides to isolate the variable and its coefficient
3B = 63
divide both sides by 3 to solve for B
B = 21
A = 5 + B = 5 + 21 = 26
Answer:
16% of its popular porcelain tile will have breaking strengths greater than 412.5 pounds per square inch.
Step-by-step explanation:
We are given that the breaking strength of its most popular porcelain tile is normally distributed with a mean of 400 pounds per square inch and a the standard deviation of 12.5 pounds per square inch.
Let X = <u><em>the breaking strength of its most popular porcelain tile</em></u>
SO, X ~ Normal(
)
The z score probability distribution for normal distribution is given by;
Z =
~ N(0,1)
where,
= mean breaking strength of porcelain tile = 400 pounds per square inch
= standard deviation = 12.5 pounds per square inch
Now, probability that the popular porcelain tile will have breaking strengths greater than 412.5 pounds per square inch is given by = P(X > 412.5)
P(X > 412.5) = P(
>
) = P(Z > 1) = 1 - P(Z
1)
= 1 - 0.84 = <u>0.16</u>
Therefore, 16% of its popular porcelain tile will have breaking strengths greater than 412.5 pounds per square inch.