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eimsori [14]
3 years ago
6

The following is the formula for finding the area (A) of a trapezoid with height (h) and bases (b1) and (b2). A = 1/2h(b1 + b2)

Which shows the formula correctly solve for the height in terms of the two bases?
A. h = 1/2A(b1 + b2)
B. h = 2A/b1 + b2
C. h = 2A - b1 - b2
D. h = A/2(b1 + b2)

Mathematics
1 answer:
charle [14.2K]3 years ago
6 0

Answer:

<em>Correct choice: B</em>

Step-by-step explanation:

<u>Equation Solving</u>

The area of a trapezoid with height h and bases b1 and b2 is given by:

\displaystyle A=\frac{1}{2}h(b_1+b_2)

We must solve this formula for h.

First, multiply by 2 to eliminate denominators:

\displaystyle 2A=h(b_1+b_2)

Now, divide by b1+b2:

\displaystyle \frac{2A}{b_1+b_2}=h

Swapping sides:

\displaystyle h=\frac{2A}{b_1+b_2}

Correct choice: B

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Angle BDR is congruent to angle QDC because they share common angles. Angles BRD and QCD are congruent because lines BR and QC are <em>parallel</em> and line DR intersecting them creates <em>two corresponding angles</em>, BRD and QCD. Because of the reasons I mentioned, Triangles DBR and DQC are similar by Angle Angle Similarity Postulate and because these two triangles are similar they must share the same scaling factor of corresponding sides (example: \frac{DQ}{DB}\\). So \frac{DQ}{DB} = \frac{DC}{DR}\\.

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