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eimsori [14]
3 years ago
6

The following is the formula for finding the area (A) of a trapezoid with height (h) and bases (b1) and (b2). A = 1/2h(b1 + b2)

Which shows the formula correctly solve for the height in terms of the two bases?
A. h = 1/2A(b1 + b2)
B. h = 2A/b1 + b2
C. h = 2A - b1 - b2
D. h = A/2(b1 + b2)

Mathematics
1 answer:
charle [14.2K]3 years ago
6 0

Answer:

<em>Correct choice: B</em>

Step-by-step explanation:

<u>Equation Solving</u>

The area of a trapezoid with height h and bases b1 and b2 is given by:

\displaystyle A=\frac{1}{2}h(b_1+b_2)

We must solve this formula for h.

First, multiply by 2 to eliminate denominators:

\displaystyle 2A=h(b_1+b_2)

Now, divide by b1+b2:

\displaystyle \frac{2A}{b_1+b_2}=h

Swapping sides:

\displaystyle h=\frac{2A}{b_1+b_2}

Correct choice: B

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Answer:

t=\frac{21.5-22}{\frac{1.5}{\sqrt{40}}}=-2.108    

p_v =P(t_{39}  

Conclusion  

If we compare the p value and the significance level given \alpha=0.01 we see that p_v>\alpha so we can conclude that we have enough evidence to FAIL to reject the null hypothesis, so we can conclude that the mean temperature actually its NOT significant less then 22 at 1% of signficance.  

(D) P-val=0.021, fail to reject the null hypothesis

Step-by-step explanation:

1) Data given and notation  

\bar X=21.5 represent the mean for the temperatures

s=1.5 represent the sample standard deviation

n=40 sample size  

\mu_o =22 represent the value that we want to test

\alpha=0.01 represent the significance level for the hypothesis test.  

t would represent the statistic (variable of interest)  

p_v represent the p value for the test (variable of interest)  

State the null and alternative hypotheses.  

We need to conduct a hypothesis in order to check if the mean is less than 22C, the system of hypothesis would be:  

Null hypothesis:\mu \geq 22  

Alternative hypothesis:\mu < 22  

If we analyze the size for the sample is > 30 and we don't know the population deviation so is better apply a t test to compare the actual mean to the reference value, and the statistic is given by:  

t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}}  (1)  

t-test: "Is used to compare group means. Is one of the most common tests and is used to determine if the mean is (higher, less or not equal) to an specified value".  

Calculate the statistic

We can replace in formula (1) the info given like this:  

t=\frac{21.5-22}{\frac{1.5}{\sqrt{40}}}=-2.108    

P-value

We can calculate the degrees of freedom like this:

df=n-1=40-1=39

Since is a one left tailed test the p value would be:  

p_v =P(t_{39}  

Conclusion  

If we compare the p value and the significance level given \alpha=0.01 we see that p_v>\alpha so we can conclude that we have enough evidence to FAIL to reject the null hypothesis, so we can conclude that the mean temperature actually its NOT significant less then 22 at 1% of signficance.  

The best option would be:

(D) P-val=0.021, fail to reject the null hypothesis

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The value of f(r - 2) is 6r - 5

<h3>What is a function?</h3>

Function can be defined as an expression, rule, or law that defines a relationship between one variable known as the independent variable and another called the dependent variable.

From the information given ,we have;

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Now, let's substitute x as r - 2 in the function given;

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