The answer is 0.8
I think that’s the answer
Answer:
Probability that at least 490 do not result in birth defects = 0.1076
Step-by-step explanation:
Given - The proportion of U.S. births that result in a birth defect is approximately 1/33 according to the Centers for Disease Control and Prevention (CDC). A local hospital randomly selects five births and lets the random variable X count the number not resulting in a defect. Assume the births are independent.
To find - If 500 births were observed rather than only 5, what is the approximate probability that at least 490 do not result in birth defects
Proof -
Given that,
P(birth that result in a birth defect) = 1/33
P(birth that not result in a birth defect) = 1 - 1/33 = 32/33
Now,
Given that, n = 500
X = Number of birth that does not result in birth defects
Now,
P(X ≥ 490) =
=
+ .......+
= 0.04541 + ......+0.0000002079
= 0.1076
⇒Probability that at least 490 do not result in birth defects = 0.1076
The answer you are looking for is x=-2.
Solution/Explanation:
Writing out the equation
3[-x+(2x+1)]=x-1
Simplifying inside of the brackets first
Combining like terms, since -x+2x=x
3(x+1)=x-1
*You can remove the parenthesis, if preferred.
Using the Distributive Property on the left side of the equation
3x+3=x-1
Now, subtracting the "x" variable from both sides
3x+3-x=x-x-1
"x-x" cancels out to 0.
3x+3-x=-1
Combining like terms and simplifying
3x-x+3=-1
2x+3=-1
Subtracting 3 from both sides of the equation
2x+3-3=-1-3
"3-3" cancels out to zero.
2x+0=-1-3
2x=-1-3
Simplifying the right side of the equation
2x=-4
Finally, dividing both sides by 2
2x/2=-4/2
Simplifying the final part of the problem
Since 2x/2=x and -4/2=-2
x=-2
So, therefore, the final answer is x=-2.
Hope that this has helped you. Good day to you.
Assuming that 2 3 is two-thirds. You will need to fill the measuring cup 9 times.
Answer:
x = 8√3
Step-by-step explanation:
Using the Pythagorean Theorem:
a² + b² = c²
x² + 8² = 16²
x² + 64 = 256
x² = 192
√x² = √192
x = √64 √3
x = 8√3