<em><u>Complete Question:</u></em>
A colony of flowers is pollinated by hummingbirds and sunbirds. Let H represents the number of hummingbirds and S represent the number of sunbirds that must pollinate the colony so it can survive until next year.
6H+ 4S> 74
This year, 8 hummingbirds pollinated the colony. What is the least number of sun birds that must pollinate the colony to ensure that it will survive until next year?
<em><u>Answer:</u></em>
The least number of sun birds is 7
<em><u>Solution:</u></em>
Given inequality is:
6H + 4S > 74
Where,
H is the number of hummingbirds
S is the number of sunbirds
This year, 8 hummingbirds pollinated the colony
Substitute H = 8 in given inequality
6(8) + 4S > 74
48 + 4S > 74
Subtract 48 from both sides
48 + 4S - 48 > 74 - 48
4S > 26
Divide both sides by 4
S > 6.5
Hence the least number of sun birds is 7
3.6 > 0.94 Hope this helps.
Answer:
x = 6
, −
6
Step-by-step explanation:
Area of square =6*6= 36 cm^2
Area of trapezoid =1/2( base1+base2)*height
base 1=7
base2=21-6=15
height=6
Area of trapezoid =1/2( 7+15)*6= 66
whole area = area of square + area of trapezoid= 36+66=102
Answer 102
Answer:
The value of the expression is 80.
Step-by-step explanation:
14 - 6 = 8.
10 x 8 = 80.
