If this is an equilateral triangle, we need half of it to find the height which is a leg of a right triangle with a hypotenuse of 15. That means that the base of this half triangle is 7.5. Use Pythagorean's Theorem to fine the height.

. x = 12.99 or 13
The half-life of the radioactive substance is 67.95 hours.
Answer:
QRT = 47, TRS = 133
Step-by-step explanation:
Since QRS is a line, QRT + TRS = 180.

Then, solve for x. Combine like terms.

Then, plug in 14 for x.

Answer:
<h3>The answer is 10.2 units</h3>
Step-by-step explanation:
The distance between two points can be found by using the formula

where
(x1 , y1) and (x2 , y2) are the points
From the question the points are
U (7,-4) and V(-3,-6)
The distance between them is

We have the final answer as
<h3>10.2 units to the nearest tenth</h3>
Hope this helps you
Answer:
D.120
Step-by-step explanation:
The sides AB and AC are equal and thus the angles they form with BC should be equal . Since now angle ABC is 30 then application of sum of angles in a triangle as a constant(180 degrees) we can subtract 60 degrees from it which gives 120