The graph looks like this, on the enclosed pic:
One feature is that it's periodic and torn (has cut-off points), meaning the domain is the same as in case of tan(x): x€R and x =/= π/2+πn.
The range equals the range of arcsin(x): -π/2<=y<=π/2 OR y€[-π/2;π/2]
Hope could understand and if it helped! :)
Answer:
Figure (i) and (iv)
Step-by-step explanation:
Given:
Optional figure is given in attached file.
We need to find two figures that are similar to the 5 by 10 figure.
All the given figure are 
form.
Where m represent the number of rows and n represent the number of columns.
Solution:
Observe that in the given figure 5 by 10, the number of rows is 5 and number of columns is 10, that is, the number of columns is double of that the number of rows.
So we need to find two such figures whose number of columns is double of the number of rows.
From the given figures, figure (i) the number of rows is 2 and number of columns is 4, which is double of number of rows. so it is similar to 5 by 10 figure.
Similarly in figure (iv), the number of rows is 4 and number of columns is 8. so the number of columns is double the number of rows, so it is similar to the figure 5 by 10.
Therefore, the two figures that are similar to 5 by 10 figure are given in attached file such as (i) and (iv).
Answer:
4
Step-by-step explanation:
- If you take the lowest half of the data (from the lower extreme to the median) and find the median of these numbers, that is called the lower quartile or quartile 1.
- If you take the upper half of the data (from the upper extreme to the median) and find the median of these numbers, that is called the upper quartile or quartile 3.
- The interquartile range is the difference between quartile 1 and quartile 3.
- 4, 5, 6, 8, 9, 10, 11, 13
- Median=8.5
- Q1=6.5
- Q3=10.5
- 10.5-6.5=4
I also added my PowerPoint if you didn't get what I was saying.
- Perpendicular=P=4
- Base=B=4
Hypotenuse be H
Apply Pythagorean theorem
You multiply... 46*13= 598 then multiply 20*6= 120 add them 598+120=$718
13a+6c=$ hope this helped you have a great rest of the day!!
