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BabaBlast [244]
2 years ago
9

5Csqrt%7B%20%5Cleft%7C%20x%20%5Cright%7C%20%7D%20%5Cright%29%20%7D%5E%7B%202%20%7D%20%3D%201" id="TexFormula1" title=" \large \tt \: { x }^{ 2 } + { \left( y- \sqrt{ \left| x \right| } \right) }^{ 2 } = 1" alt=" \large \tt \: { x }^{ 2 } + { \left( y- \sqrt{ \left| x \right| } \right) }^{ 2 } = 1" align="absmiddle" class="latex-formula">
Solve for y. Attach a graph too.
Note :- The graph will come in the shape of a heart.

Only solve if you know it!​​
Mathematics
2 answers:
Gennadij [26K]2 years ago
8 0

Refer to the attachment

wel2 years ago
5 0

\huge \boxed{\mathbb{QUESTION} \downarrow}

  • \large \tt \: { x }^{ 2 } + { \left( y- \sqrt{ \left| x \right| } \right) }^{ 2 } = 1

\large \boxed{\mathfrak{Answer \: with \: Explanation} \downarrow}

{ x  }^{ 2  }  + {  \left( y- \sqrt{  \left| x  \right|    }    \right)    }^{ 2  }   =  1

Subtract x² from both sides of the equation.

\left(y-\sqrt{|x|}\right)^{2}+x^{2}-x^{2}=1-x^{2}

Subtracting x² from itself leaves 0.

\left(y-\sqrt{|x|}\right)^{2}=1-x^{2}

Take the square root of both sides of the equation.

y-\sqrt{|x|}=\sqrt{1-x^{2}}  \\ y-\sqrt{|x|}=-\sqrt{1-x^{2}}

Subtract − √∣x∣ from both sides of the equation.

y-\sqrt{|x|}-\left(-\sqrt{|x|}\right)=\sqrt{1-x^{2}}-\left(-\sqrt{|x|}\right)  \\ y-\sqrt{|x|}-\left(-\sqrt{|x| } \right)=-\sqrt{1-x^{2}}-\left(-\sqrt{|x|}\right)

Subtracting − √∣x∣ from itself leaves 0.

y=\sqrt{1-x^{2}}-\left(-\sqrt{|x|}\right) \\  y=-\sqrt{1-x^{2}}-\left(-\sqrt{|x|}\right)

Subtract − √∣x∣from √1- x².

\underline{\underline{ \sf \: y=\sqrt{1-x^{2}}+\sqrt{|x|} }}

Subtract − √∣x∣from - √1- x².

\underline{\underline{ \sf \: y= - \sqrt{1-x^{2}}+\sqrt{|x|} }}

The equation is now solved.

\large \boxed{ \boxed{ \bf \: y=\sqrt{1-x^{2}}+\sqrt{|x|} }}\\   \\   \large\boxed {\boxed{ \bf \: y=-\sqrt{1-x^{2}}+\sqrt{|x|} }}

_________________________________

  • Refer to the attached image for the graph.

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38% of 1200 Otto middle school students are 6th how many auto students are sixth graders
kramer

Answer:

456 students

Step-by-step explanation:

38% = 0.38

1200 x 0.38 = 456

6 0
2 years ago
Are these numbers rational or irrational? √10 (square root of 10) √16 (square root of 16) 52% 1.235 1. Rational 2. Irrational pl
77julia77 [94]

Step-by-step explanation:

any rational number can be expressed as a/b, with a and b being integer numbers, and b different to 0.

-7 = -7/1 rational

sqrt(10) irrational (because there is no rational number multiplied by itself that results in 10)

sqrt(16) = sqrt(4×4) = 4 = 4/1 rational

52% = 52/100 rational

1.235 = 1235/1000 rational

5 0
2 years ago
The following data show the prices of different types of outfits at a store: $2, $2, $28, $26, $25, $27, $25, $27, $26, $28, $30
arlik [135]

2, 2, 25, 25, 26, 26, 27, 28, 28, 30

Minimum: 2

Maximum: 30

Median: 26

Lower quartile: 25

Upper quartile: 28

The box plot will have its left tail longer than the right tail because a few exceptionally low prices make the distribution skewed to the left.

<em>Just so you know, I didn't write this. Next time, do a google search for your answer. But in the mean time, here you go.</em>



6 0
3 years ago
Without using a trigonometric ratio, find the distance from the ship to the buoy, B. Round the distance to the nearest tenth of
alexdok [17]
Without using the trigonometry ratio, we can find the distance between the ship and the buoy by:

the distance between City and Lemont SUBTRACT the vertical distance between City and the point parallel to the Ship

The distance between the City and Lemont can be worked out using the Sin rule 
\frac{57.8}{sin(36)}= \frac{City-Lemont}{sin(92)}
City-Lemont= \frac{57.9sin(92)}{sin(36)} = 98.27.....≈98.3

The vertical distance between the City and the point parallel to the ship can be worked out using the Pythagoras theorem
\sqrt{57.8^{2}- 44.6^{2} } =36.765...≈36.8

The distance between the ship and the Buoy is given:
98.3-36.8=61.5 miles

5 0
3 years ago
What is (g•f)(2). ?
Leona [35]
G(F(2))
So f would be x
-(2x+1)-2 you slove it and get you answer and plug the answer back into the equation above as x
-(2(answer)+1)-2
Hope this helps
5 0
3 years ago
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