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BigorU [14]
3 years ago
12

The profile picture that you plan to use to market your professional brand on social media networks should feature you only.

Computers and Technology
1 answer:
ArbitrLikvidat [17]3 years ago
6 0

Answer:

false

Explanation:

You might be interested in
Write a program that declares a two-dimensional array named myFancyArray of the type double. Initialize the array to the followi
kirill115 [55]

Answer:

This solution is provided in C++

#include <iostream>

using namespace std;

double sumFancyArray(double myarr[][6]){

   double sum = 0.0;

   for(int i = 0;i<2;i++)    {

       for(int j = 0;j<6;j++){

       sum+=myarr[i][j];    

       }}    

   return sum;

}

void printFancyArray(double myarr[][6]){

   for(int i = 0;i<2;i++)    {

       for(int j = 0;j<6;j++){

       cout<<myarr[i][j]<<" ";    

       }

   }

}

int main(){

   double myFancyArray[2][6] = {23, 14.12, 17,85.99, 6.06, 13, 1100, 0, 36.36, 90.09, 3.145, 5.4};

   cout<<sumFancyArray(myFancyArray)<<endl;

   printFancyArray(myFancyArray);

   

   return 0;

}

Explanation:

This function returns the sum of the array elements

double sumFancyArray(double myarr[][6]){

This initializes sum to 0

   double sum = 0.0;

This iterates through the row of the array

   for(int i = 0;i<2;i++)    {

This iterates through the column

       for(int j = 0;j<6;j++){

This adds each element

       sum+=myarr[i][j];    

       }}    

This returns the sum

   return sum;

}

This method prints array elements

void printFancyArray(double myarr[][6]){

This iterates through the row of the array

   for(int i = 0;i<2;i++)    {

This iterates through the column

       for(int j = 0;j<6;j++){

This prints each array element

       cout<<myarr[i][j]<<" ";    

       }

   }

}

The main starts here

int main(){

This declares and initializes the array

   double myFancyArray[2][6] = {23, 14.12, 17,85.99, 6.06, 13, 1100, 0, 36.36, 90.09, 3.145, 5.4};

This calls the function  that returns the sum

 cout<<sumFancyArray(myFancyArray)<<endl;

This calls the function that prints the array elements

   printFancyArray(myFancyArray);

   

   return 0;

}

Download cpp
7 0
3 years ago
It is ________ to pass an argument to a function that contains an individual array element, such as numbers[3].
Lapatulllka [165]

Answer:

The answer is "option B".

Explanation:

In the C++ programming language, it is legal to pass a parameter in the method that includes an individual array element. where an array is a collection of homogeneous (similar types of) elements. and other options are not correct that can be defined as:

  • In option, a Passing argument in a function is not illegal in c++.
  • In option c, It is recommended by the ANSI committee.
  • In option d, It is good for practice in coding.
5 0
3 years ago
. Create an abstract Dollar class with two integer attributes, both of which are non-public (Python programmers - it is understo
aksik [14]

Answer:

Explanation:

The following code is written in Java. It creates the abstract dollar class that has two instance variables for the dollars and the coins that are passed as arguments. The test output can be seen in the picture attached below.

class Dollar {

   int dollars;

   double coin;

   private Dollar(int dollar, int coin) {

       this.dollars = dollar;

       this.coin = Double.valueOf(coin) / 100;

   }

   

}

4 0
3 years ago
Which image file format is the most widely used?
Ostrovityanka [42]

Answer: jpeg because its a lot of people use it for quaity

7 0
2 years ago
Write a program that reads in a list of numbers, and for each number, determines and prints out whether or not that number is ab
adelina 88 [10]
int IsAbundant(int n)
{
int divisorSum = 0;
for (int i = 1; i < n; i++) {
 if ((n % i) == 0) {
  divisorSum += i;
 }
}
return divisorSum > n;
}


int main()
{
int number = 0;
do {
 printf("Enter a number (0 to quit): ");
 scanf_s("%d", &number);
 if (IsAbundant(number)) {
  printf("%d is abundant!\n", number);
   } else
   {
    printf("%d is not abundant.\n", number); }
   } while (number > 0);

   return 0;
}

7 0
3 years ago
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