Answer:
The change in the car's distance is 8 feet
Step-by-step explanation:
* Lets explain how to solve the problem
- A car is driving away from a crosswalk
- The distance d (in feet) of the car from the crosswalk t seconds
since the car started moving is given by the formula d = t² + 3.5
- The time increasing from 1 second to 3 seconds
- We need to now the change of the car's distance from the crosswalk
∵ The equation of the distance is d = t² + 3.5
∵ The time is 1 second
∴ d = (1)² + 3.5
∴ d = 1 + 3.5 = 4.5 feet
∵ The time is 3 seconds
∴ d = (3)² + 3.5
∴ d = 9 + 3.5 = 12.5 feet
∵ The change of the distance = d of 3 sec - d of 1 sec
∵ d of 3 sec = 12.5 feet
∵ d of 1 sec = 4.5 feet
∴ The change of the distance = 12.5 - 4.5 = 8 feet
∴ The change in the car's distance is 8 feet
Answer:
(x−2)^3=x^3−6x^2+12x-8
Step-by-step explanation:
if you are talking about the binomial (x−2)^3 you must expand then simplify. (x-2)3 you would just remove the parenthesizes and multiply -2 with 3 to get x-6 but I think you meant (x-2)^3
Answer:
x = 120
Step-by-step explanation:
Since they are supplementary, they add up to 180 degrees.
So, you can say x + x/2 = 180
Then, you would solve it like an algebra problem.
Multiply both sides by 2
2x + x = 360
Simplify
3x = 360
Divide both sides by 3
x = 120
Answer:
Ok so lets break it down.
Step-by-step explanation:
5-2 = 3 now we have 1/4 and 1/10 10 divided by 4 = 2.5
So we can convert it then we have 2.5 out of ten.
then we add them up equals 3.5 out of ten.
Now we have 3.3.5 So now all we do is have to add 2.
