A square has: 3 lines of symmetry 4 lines of symmetry 2 lines of symmetry
2 answers:
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Answer:
The points for the given to linear equations is (5 , - 2) and (5 , - 1)
The points is plotted on the graph shown .
Step-by-step explanation:
Given as :
The two linear equation are
y = x - 1 ...........1
y = x - 6 ...........2
Now, Solving both the linear equations
Put the value of y from eq 2 into eq 1
I.e x - 6 =
x - 1
Or, x +
x = 6 - 1
Or, x = 5
or, x = 5
∴ x = 5
Now, Put the value of x in eq 1
So, y = x - 1
Or, y = × 5 - 1
or, y = - 1
Or, y = - 1 - 1
I.e y = -2
So, For x = 5 , y = - 2
Point is ( ,
) = (5 , - 2)
Again , put the value of x in eq 2
So, y = x - 6
Or, y = × 5 - 6
Or, y = - 6
Or, y = 4 - 6
I.e y = - 2
So, For x = 5 , y = - 2
Point is ( ,
) = (5 , - 2)
Hence, The points for the given to linear equations is (5 , - 2) and (5 , - 2)
The points is plotted on the graph shown . Answer
Answer:
m∠ADC = 132°
Step-by-step explanation:
From the figure attached,
By applying sine rule in ΔABD,
sin(∠ADB) =
= 0.74231
m∠ADB =
= 47.92°
≈ 48°
m∠ADC + m∠ADB = 180° [Linear pair of angles]
m∠ADC + 48° = 180°
m∠ADC = 180° - 48°
m∠ADC = 132°