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FromTheMoon [43]
3 years ago
10

Carpeta de recuperación

Mathematics
1 answer:
Wewaii [24]3 years ago
7 0

Answer:

nose porque yo no entiendo referencias

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Tara noticed that the tape she was using to wrap packages was 2 centimeters wide. How many meters wide was the tape?
Vikentia [17]
2 centimeters converts to 0.02 meters. Hope this helped!
8 0
3 years ago
How far apart in feet are Marcus and Joel. Please round your answer to the nearest tenth of a foot
Pavel [41]

Answer:

The distance between Marcus and Joel is approximately 127.3 feet.

Step-by-step explanation:

The distances between Jean to Joel, Jean to Marcus and Marcus to Joel form a right triangle where the distance from Marcus to Joel is the hypothenuse. We can measure the distance from Jean to Marcus and Jean to Joel by using the grid provided, since they're along the same axis. This is shown below:

d(Jean, Marcus) = Jean(x) - Marcus(x) = 100 - 10 = 90 feet

d(Jean, Joel) = Jean(y) - Joel(y) = 90 - 0 = 90 feet

We can apply the pythagora's theorem to find the distance between Marcus and Joel.

d(Marcus,Joel)² = d(Jean,Marcus)² + d(Jean,Joel)²

d(Marcus,Joel)² = (90)² + (90)²

d(Marcus,Joel)² = 2*(90)²

d(Marcus, Joel) = sqrt(2*(90)²) = 90*sqrt(2) = 127.279 feet

The distance between Marcus and Joel is approximately 127.3 feet.

8 0
3 years ago
The blueprint of a rectangular house is 2.5 inches by 1.5 inches. If the scale is 1:20, what is the perimeter of the actual hous
defon

Answer:

160

Step-by-step explanation:

(2.5 x 2)+(1.5 x 2) =8      (perimeter of scale)

8x20 = 160

4 0
3 years ago
Cynthia Besch wants to buy a rug for a room that is 21 ft wide and 34 ft long. She wants to leave
Daniel [21]

Answer:

Dimensions of the rug = 13 ft × 26 ft

Step-by-step explanation:

Dimensions of the room = 21 ft × 34 ft

Area of the room = 21 × 34 = 714 ft²

Cynthia wants to leave a uniform strip of floor around the rug.

Let the width of the rug = x ft

Then the dimensions of the rug will be = (21- 2x)ft × (34 - 2x)ft

Area of the rug = (21 - 2x)×(34 - 2x) square feet

338 = (21 - 2x)×(34 - 2x)

338 = 714 - 68x - 42x + 4x²

4x² - 110x + 714 - 338 = 0

4x² - 110x + 376 = 0

2x² - 55x + 188 = 0

2x² - 47x - 8x + 188 = 0

x(2x - 47) - 8(x - 47) = 0  

(x - 4)(2x - 47) = 0

x = 4, \frac{47}{2}

For x = 23.5 area of the rug will be negative.

Therefore, x = 4 ft will be the width of the rug.

Dimensions of the rug will be 13 ft × 26 ft. 

7 0
3 years ago
How to solve these question?
mart [117]
3.) An extreme value refers to a point on the graph that is possibly a maximum or minimum. At these points, the instantaneous rate of change (slope) of the  graph is 0 because the line tangent to the point is horizontal. We can find the rate of change  by taking the derivative of the function.

y' = 2ax + b

Now that we where the derivative, we can set it equal to 0.

2ax + b = 0

We also know that at the extreme value, x = -1/2. We can plug that in as well.

2a (-\frac{1}{2} ) + b = 0

The 2 and one-half cancel each other out.

-a + b = 0

a = b

Now we know that a and b are the same number, and that ax^2 + bx + 10 = 0 at x = -1/2. So let's plug -1/2 in for x in the original function, and solve for a/b.

a(-0.5)^2 + a(-0.5) + 10 = 0

0.25a - 0.5a + 10 = 0

-0.25a = -10

a = 40

b = 40

To determine if the extrema is a minima or maxima, we need to go back to the derivative and plug in a/b.

80x + 40

Our critical number is x = -1/2. We need to plug a number that is less than -1/2  and a number that is greater than -1/2 into the derivative.

LESS THAN:
80(-1) + 40 =  -40

GREATER THAN:
80(0) + 40 = 40

The rate of change of the graph changes from negative  to positive at x = -1/2, therefore the extreme value is a minimum.

4.) If the quadratic function is symmetrical about x = 3, that means that the minimum or maximum must be at x = 3.

y' = 2ax + 1

2a(3) + 1 = 0

6a = -1

a = -1/6

So now plug the a value and x=3 into the original function to find the extreme value.

(-1/6)(3)^2 + 3 + 3 = 4.5

The extreme value is 4.5


7 0
3 years ago
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