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3 years ago

15

The line plot below shows data on the total number of hours that each volunteer spent at a nature center one week. Which questio

n cannot be answered using the data in the graph

2 answers:

3241004551 [841]3 years ago

7 0

Answer:

How many volunteers worked a total of 4 hours

Step-by-step explanation:

Its right i got a one hundred my test

irina [24]3 years ago

5 0

Answer:

How many volunteers worked at a total of 4 hours?

Step-by-step explanation:

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A square garden plot measures 44 yards on each side. What is the length of the diagonal of this plot?

gogolik [260]

Answer:

44√2 yards ≈ 62.23 yards

Step-by-step explanation:

You can uses the Pythagorean theorem to find the length of the diagonal. It is the hypotenuse of a right triangle with side lengths of 44 yards. Then the diagonal measure is ...

d = √(44² +44²) = √(44² × 2) = 44√2

The length of the diagonal of the plot is 44√2 yards, about 62.23 yards.

8 0

4 years ago

Find mZDOC.<br> A)<br> 22°<br> B)<br> 44°<br> C)<br> 107<br> D)<br> 126

Snezhnost [94]

Answer:

timber

Step-by-step explanation:

nobody has ever seen a single person in the world

3 0

3 years ago

Q1. An airplane flies with a constant speed of 600 miles per hour. How far can it travel in 3 1/2 hours?

Dahasolnce [82]

Answer:

Q1. 1050 miles

Q2. 1h 30m

Step-by-step explanation:

Q1. 1h = 300 miles

3 $\frac{1}{2}$ h = 3.5 × 300 miles

= 1050 miles

Q2. 68km = 1h

102km = $\frac{102}{68}$ × 1h

= 1.5h

= 1h 30m

5 0

3 years ago

What does x equals (x+16)

Brut [27]

Answer:

x+16=4x-5. {being vertically opposite angle}

16+5=4x-x

21=3x

or, 21/3=x

hence, x=7

8 0

3 years ago

Read 2 more answers

Solve the system of equation by guess sidle method

lilavasa [31]

Answer: The solution is,

$x_1\approx 0.876$

$x_2\approx 0.419$

$x_3\approx 0.574$

Step-by-step explanation:

Given equations are,

$8x_1 + x_2 + x_3 = 8$

$2x_1 + 4x_2 + x_3 = 4$

$x_1 + 3x_2 + 5x_3 = 5$ ,

From the above equations,

$x_1=\frac{1}{8}(8-x_2-x_3)$

$x_2=\frac{1}{4}(4-2x_1-x_3)$

$x_3=\frac{1}{5}(5-x_1-3x_2)$

First approximation,

$x_1(1)=\frac{1}{8}(8-(0)-(0))=1$

$x_2(1)=\frac{1}{4}(4-2(1)-(0))=0.5$

$x_3(1)=\frac{1}{5}(5-1-3(0.5))=0.5$

Second approximation,

$x_1(2)=\frac{1}{8}(8-(0.5)-(0.5))=0.875$

$x_2(2)=\frac{1}{4}(4-2(0.875)-(0.5))=0.4375$

$x_3(2)=\frac{1}{5}((0.875)-3(0.4375))=0.5625$

Third approximation,

$x_1(3)=\frac{1}{8}(8-(0.4375)-(0.5625))=0.875$

$x_2(3)=\frac{1}{4}(4-2(0.875)-(0.5625))=0.421875$

$x_3(3)=\frac{1}{5}(5-(0.875)-3(0.421875))=0.571875$

Fourth approximation,

$x_1(4)=\frac{1}{8}(8-(0.421875)-(0.571875))=0.875781$

$x_2(4)=\frac{1}{4}(4-2(0.875781)-(0.571875))=0.419141$

$x_3(4)=\frac{1}{5}(5-(0.875781)-3(0.419141))=0.573359$

Fifth approximation,

$x_1(5)=\frac{1}{8}(8-(0.419141)-(0.573359))=0.875938$

$x_2(5)=\frac{1}{4}(4-2(0.875938)-(0.573359))=0.418691$

$x_3(5)=\frac{1}{5}(5-(0.875938)-3(0.418691))=0.573598$

Hence, by the Gauss Seidel method the solution of the given system is,

$x_1\approx 0.876$

$x_2\approx 0.419$

$x_3\approx 0.574$

4 0

3 years ago