Y2 + x2 = 53
y − x = 5
y = 5 + x
(5+x)^2 + x^2 = 53
(5+x)(5+x) + x^2 = 53
25 + 10x + x^2 +x^2 = 53
2x^2 + 10x - 28 = 0
(x-2)(x+7)=0
x = 2 , x = - 7
y = 5 + 2
y = 7
y = 5 +(-7)
y = 5 - 7
y = - 2
Answer:
4/5x+3
Step-by-step explanation:
remove the useless parenthesis, then calculate the x sum then the normal numbers sum
Answer:
7x+4
Step-by-step explanation:
Distribute:
=(3)(4x)+(3)(−2)+−5x+10
=12x+−6+−5x+10
Combine Like Terms:
=12x+−6+−5x+10
=(12x+−5x)+(−6+10)
=7x+4
X=10
-3 on both sides
Then -6(x+4)+3 to the other side
