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joja [24]
3 years ago
10

An animal shelter reports that the number of dogs in the shelter is 6 less than twice the number of cats. There are a total of 1

59 animals in the shelter.
Mathematics
2 answers:
Anna71 [15]3 years ago
7 0
159/2 =79-6
the answer is 73
igomit [66]3 years ago
7 0
Your answer is most likely 59 not 100 percent sure but i am 89 percent sure 
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steposvetlana [31]
Tbh idrk but uh thanks for the points
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3 years ago
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Graph the linear equation.find three points that solve the equation, then plot on the graph. -4y=x-18
kirill [66]

Step-by-step explanation:-

-4y goes on the y axis

and 18 goes on the x axis

5 0
3 years ago
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Hello brainly please help me with this
Sedaia [141]

Answer:

No

Step-by-step explanation:

By multiplying 1/3 4 times, you would get 1/81 because you are multiplying the numerators by the numerators and the denominators by the denominators. However Priya is adding the fractions instead which gave her 4/3

I hope this helped xd

4 0
2 years ago
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Malcolm and Ravi raced each other. The average of their maximum speeds was 260\text{ km/h}260 km/h260, space, k, m, slash, h. If
nikdorinn [45]

Let m and r represent the maximum speeds of Malcolm and Ravi in km/h, respectively.

... (m + r)/2 = 260 . . . . . the average of their speeds was 260 kph

... 2m = r + 80 . . . . . . . . double Malcolm's speed is 80 kph more than Ravi's

The second equation can be solved for r and that expression substituted into the first equation.

... 2m - 80 = r . . . . . . . . . . . an expression for r from the second equation

... (m + 2m - 80)/2 = 260 . . . the result of substituting that into the first

... 3m - 80 = 520 . . . . . . . . multiply by 2

... m = 200 . . . . . . . . . . . . . add 80 and divide by 3

... 2·200 - 80 = r = 320 . . .substitute the value of m into the expression for r

Malcolm's maximum speed was 200 km/h.

Ravi's maximum speed was 320 km/h.

6 0
3 years ago
We wish to give a 90% confidence interval for the mean value of a normally distributed random variable. We obtain a simple rando
coldgirl [10]

Answer: (9.27025,\ 11.12975)

Step-by-step explanation:

Given : Sample size : n= 9

Degree of freedom = df =n-1 =8

Sample mean : \overline{x}=10.2

sample standard deviation : s= 1.5

Significance level ; \alpha= 1-0.90=0.10

Since population standard deviation is not given , so we use t- test.

Using t-distribution table , we have

Critical value = t_{\alpha/2, df}=t_{0.05 , 8}=1.8595

Confidence interval for the population mean :

\overline{x}\pm t_{\alpha/2, df}\dfrac{s}{\sqrt{n}}

90% confidence interval for the mean value will be :

10.2\pm (1.8595)\dfrac{1.5}{\sqrt{9}}

10.2\pm (1.8595)\dfrac{1.5}{3}

10.2\pm (1.8595)(0.5)

10.2\pm (0.92975)

(10.2-0.92975,\ 10.2+0.92975)

(9.27025,\ 11.12975)

Hence, the 90% confidence interval for the mean value= (9.27025,\ 11.12975)

6 0
3 years ago
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