<span>Polyethylene terephthalate formed into a cup shape. The components of polyethylene terephthalate are carbon, hydrogen and oxygen.</span>
Answer: a) 0.070 moles of oxygen were produced.
b) New pressure due to the oxygen gas is 2.4 atm
Explanation:
According to ideal gas equation:
P = pressure of gas = 2.7 atm
V = Volume of gas = 700 ml = 0.7 L
n = number of moles = ?
R = gas constant =
T =temperature = 329 K
Thus 0.070 moles of oxygen were produced.
When the 700 mL flask cools to a temperature of 293K.
The new pressure due to the oxygen gas is 2.4 atm
5.5/-38 / 5.5 = 1/-6.9 x 1.3 = 1.3/-8.98
unit volume/temperature x searching amount
i’d say the temperature would be -8.98 C simply - I don’t know what formula youd use for this
Answer:
a. 1.23 V
b. No maximum
Explanation:
Required:
a. Is there a minimum standard reduction potential that the half-reaction used at the cathode of this cell can have?
b. Is there a maximum standard reduction potential that the half-reaction used at the cathode of this cell can have?
The standard cell potential (E°cell) is the difference between the standard reduction potential of the cathode and the standard reduction potential of the anode.
E°cell = E°red, cat - E°red, an
If E°cell must be at least 1.10 V (E°cell > 1.10 V),
E°red, cat - E°red, an > 1.10 V
E°red, cat - 0.13V > 1.10 V
E°red, cat > 1.23 V
The minimum standard reduction potential is 1.23 V while there is no maximum standard reduction potential.
Answer:
12 moles of propane.
Explanation:
From the question given above, the following data were obtained:
Volume (V) = 216 L
Pressure (P) = 184.8 KPa
Temperature (T) = 127 °C
Number of mole (n) =?
Next, we shall convert 127 °C to Kelvin temperature. This can be obtained as follow:
T(K) = T(°C) + 273
T(°C) = 127 °C
T(K) = 127 + 273
T(K) = 400 K
Finally, we shall determine the number of mole of propane gas in the container. This can be obtained as follow:
Volume (V) = 216 L
Pressure (P) = 184.8 KPa
Temperature (T) = 400 K
Gas constant (R) = 8.314 L.KPa/Kmol
Number of mole (n) =?
PV = nRT
184.8 × 216 = n × 8.314 × 400
39916.8 = n × 3325.6
Divide both side by 3325.6
n = 39916.8 / 3325.6
n = 12 moles
Thus, 12 moles of propane is present in the cylinder
