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ValentinkaMS [17]
3 years ago
9

What is the correct formula for Strontium Selenide?

Chemistry
1 answer:
ikadub [295]3 years ago
5 0

Answer:

(SrSe) | SeSr - PubChem.

Explanation:

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Name the following compounds CaSe <br><br> don’t use common names such as water or salt
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3 years ago
A chunk of zinc is added to a solution of gold (III) nitrate to extract the gold. The reaction forms,
alina1380 [7]

Answer:

it forms :

1. Gold ( Au )

2. Zinc nitrate ( Zn(NO3)2 )

Explanation:

When a chunk of zinc is added to a solution of gold (III) nitrate to extract the gold. The reaction forms Gold and Zinc nitrate .

it's a single displacement reaction,

here's the balanced equation for above reaction :

3 Zn + 2 Au(NO3)3 =》3 Zn(NO3)2 + 2 Au

7 0
3 years ago
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Explain why the nucleus of an atom is positively charged but the overall charge of an atom is neutral
gtnhenbr [62]

Answer:

The nucleus is positively charged because it contains all of the protons however the charge of an atom is neutral because there is an equal amount of protons (positive) and electrons (negative) meaning the opposite charges cancel each other out therefore making the atoms overall charge neutral.

Explanation:

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3 years ago
On the window sill is a potted plant. The plant always seems to lean toward the window. Even though you turn its pot around ever
ICE Princess25 [194]

Answer:

because im trynna get these 5 points

Explanation:

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3 0
3 years ago
Ethylenediamine (en) forms an octahedral complex with Ni2+(aq) with the formula [Ni(en)3]2+. Ni2+(aq) + 3 en ⇌ [Ni(en)3]2+(aq) K
yawa3891 [41]

Answer:

3.125\times 10^{-19} mol/L is the concentration of Ni^{2+}(aq) in the solution.

Explanation:

Ni^{2+}(aq) + 3 en\rightleftharpoons [Ni(en)_3]^{2+}(aq)

Concentration of nickel ion = [Ni^{2+}]=x

Concentration of nickel complex= [[Ni(en)_3]^{2+}]=\frac{0.16 mol}{2 L}=0.08 mol/L

Concentration of ethylenediamine = [en]=\frac{0.80 mol}{2 L}=0.40 mol/L

The formation constant of the complex = K_f=4.0\times 10^{18}

The expression of formation constant is given as:

K_f=\frac{[[Ni(en)_3]^{2+}]}{[Ni^{2+}][en]^3}

4.0\times 10^{18}=\frac{0.08 mol/L}{x\times (0.40 mol/L)^3}

x=\frac{0.08 mol/L}{4.0\times 10^{18}\times (0.40 mol/L)^3}

x=3.125\times 10^{-19} mol/L

3.125\times 10^{-19} mol/L is the concentration of Ni^{2+}(aq) in the solution.

6 0
4 years ago
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