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4 years ago

35 POINTS, Please help me with this high school geometry question.

Mathematics

1 answer:

Pani-rosa [81]4 years ago

5 0

Answer:

A: part 1:

A. (-5,6)

B. (2,5)

C. (-2,-4)

Step-by-step explanation:

B: Part 2:

A. (-2,4) ---> (-5,6): moved left 3 times, moved up 2 times.

B. (5,3) ----> (2,5): moved left 3 times, moved right 2 times.

C. (1,-6) ----> (-2,-4): moved left 3 times, moved right 2 times.

Hope this helps you!! (:

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3 years ago

Karel the Dog is instructed to move forward three spaces. Then, if Karel is standing on a ball, Karel will turn right and move f

Klio2033 [76]

Complete Question

The diagram for the question is shown on the first uploaded image

Answer:

The final position of Karel is shown on the second uploaded image

Step-by-step explanation:

On the diagram the dot represents steps to be taken by Karel

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3 years ago

West of Checkpoint A, which is at (0,5), are two hurdles that Helena needs to jump over. Hurdle 1 is 4 units west of Checkpoint

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Answer:

Coordinate of Checkpoint B is (-9,5)

Step-by-step explanation:

Here is an inserted image of the graph and coordinates.

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3 years ago

What is the simplified expression for,

Nostrana [21]

Here are a few rules you need to know for this equation:

Multiplying exponents of the same base: $x^m\times x^n=x^{m+n}$
Dividing exponents of the same base: $\frac{x^m}{x^n}=x^{m-n}$
Turning a negative exponent to a positive one: $x^{-m}=\frac{1}{x^m};\frac{1}{x^{-m}}=x^m$

So this is our algebraic expression: $\frac{3^{-4}\times 2^3\times 3^2}{2^4\times 3^{-3}}$

Firstly, multiply 3^-4 and 3^2: $\frac{3^{-4+2}\times 2^3}{2^4\times 3^{-3}}=\frac{3^{-2}\times 2^3}{2^4\times 3^{-3}}$

Next, divide:

$\frac{3^{-2}\times 2^3}{2^4\times 3^{-3}}=3^{-2-(-3)}2^{3-4}=3^12^{-1}$

Next, turn the negative exponent into a positive one: $3^12^{-1}= \frac{3}{2}$

<u>Your final answer is 3/2, or 1.5.</u>

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3 years ago

Which equation is the inverse of 5y+4= (x+3)² + 2?

Neko [114]

I think this is the answer to your question And also the solution

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2 years ago