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Mademuasel [1]
2 years ago
13

Hurry friends, don't write it blank X= 72 Work 2x+ 52159x What

Mathematics
1 answer:
Scilla [17]2 years ago
3 0

Answer:

Step-by-step explanation:

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The dimensions of a square prism are 2 centimeters by 2 centimeters by 12 centimeters. What is its surface area?
Pani-rosa [81]

Answer:

The  surface area of the square prism is 104\ cm^{2}

Step-by-step explanation:

we know that

The surface area of the square prism is equal to  

SA=2b^{2} +4bh

where

b is the length side of the square base

h is the height of the prism

In this problem we have

b=2\ cm

h=12\ cm

substitute

SA=2(2)^{2} +4(2)(12)=104\ cm^{2}

7 0
3 years ago
You make $10 on the first day, $20 on the second day, $40 on the third day, $80 on the fourth day, and so on. What is your total
Trava [24]
The answer to this question is 5,120 you have to multiply by 2
4 0
2 years ago
What is the value of the expression (–5) -3? It’s -125
Hoochie [10]

Answer:

Step-by-step explanation:

The correct answer would actually be 15 because (-5) multiplied by -3 makes it positive 15.

3 0
3 years ago
Read 2 more answers
Solve by substitution <br> X^2= 2y + 10<br> 3x-y = 9
Viefleur [7K]

Answer:

x=-4\\ x=-2\\ y=-21\\ y=-15

Step-by-step explanation:

x^{2} =2y+10

y=-9+3x

x^{2} =2(-9+3x)+10

x^{2} =-18+6x+10

x^{2} =6x-8

x^{2} -6x+8

x=-4, -2

y=-9+3(-4)

y=-9-12

y=-21

y=-9+3(-2)

y=-9-6

y=-15

8 0
3 years ago
Read 2 more answers
Three populations have proportions 0.1, 0.3, and 0.5. We select random samples of the size n from these populations. Only two of
IRINA_888 [86]

Answer:

(1) A Normal approximation to binomial can be applied for population 1, if <em>n</em> = 100.

(2) A Normal approximation to binomial can be applied for population 2, if <em>n</em> = 100, 50 and 40.

(3) A Normal approximation to binomial can be applied for population 2, if <em>n</em> = 100, 50, 40 and 20.

Step-by-step explanation:

Consider a random variable <em>X</em> following a Binomial distribution with parameters <em>n </em>and <em>p</em>.

If the sample selected is too large and the probability of success is close to 0.50 a Normal approximation to binomial can be applied to approximate the distribution of X if the following conditions are satisfied:

  • np ≥ 10
  • n(1 - p) ≥ 10

The three populations has the following proportions:

p₁ = 0.10

p₂ = 0.30

p₃ = 0.50

(1)

Check the Normal approximation conditions for population 1, for all the provided <em>n</em> as follows:

n_{a}p_{1}=10\times 0.10=1

Thus, a Normal approximation to binomial can be applied for population 1, if <em>n</em> = 100.

(2)

Check the Normal approximation conditions for population 2, for all the provided <em>n</em> as follows:

n_{a}p_{1}=10\times 0.30=310\\\\n_{c}p_{1}=50\times 0.30=15>10\\\\n_{d}p_{1}=40\times 0.10=12>10\\\\n_{e}p_{1}=20\times 0.10=6

Thus, a Normal approximation to binomial can be applied for population 2, if <em>n</em> = 100, 50 and 40.

(3)

Check the Normal approximation conditions for population 3, for all the provided <em>n</em> as follows:

n_{a}p_{1}=10\times 0.50=510\\\\n_{c}p_{1}=50\times 0.50=25>10\\\\n_{d}p_{1}=40\times 0.50=20>10\\\\n_{e}p_{1}=20\times 0.10=10=10

Thus, a Normal approximation to binomial can be applied for population 2, if <em>n</em> = 100, 50, 40 and 20.

8 0
3 years ago
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