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2 years ago

8

The rides at an amusement park have restrictions based on height. For the Swan Ride, the minimum height is 2 feet and the maximu

m height is 3 feet. Write and solve an absolute value equation that has these minimum and maximum heights as its solutions.

1 answer:

Stolb23 [73]2 years ago

5 0

Answer:

11 feet

Step-by-step explanation:

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Alonzo works as a tutor for $7 an hour and as a waiter for $8 an hour this month he worked a combined total dollar total dollar

docker41 [41]

Answer: -1t + 720

Step-by-step explanation:

He worked at both jobs for 90 hours for this month.

He worked t hours as a tutor which means that as a waiter he worked;

= 90 - t hours

The amount earned is therefore;

= 7t + (8 * (90 - t))

= 7t + 720 - 8t

= -1t + 720

6 0

3 years ago

Find parametric equations for the sphere centered at the origin and with radius 3. Use the parameters s and t in your answer.

sdas [7]

Radius, r = 3

The equation of a sphere entered at the origin in cartesian coordinates is

x^2 + y^2 + z^2 = r^2

That in spherical coordinates is:

x = rcos(theta)*sin(phi)
y= r sin(theta)*sin(phi)
z = rcos(phi)

where you can make u = r cos(phi) to obtain the parametrical equations

x = √[r^2 - u^2] cos(theta)
y = √[r^2 - u^2] sin (theta)
z = u

where theta goes from 0 to 2π and u goes from -r to r.

In our case r = 3, so the parametrical equations are:

Answer:
x = √[9 - u^2] cos(theta)
y = √[9 - u^2] sin (theta)
z = u

6 0

3 years ago

Read 2 more answers

It rained 10% of the 30 days last month.on how many days did it not rain?

drek231 [11]

10% of 30 is 3, which means it rained 3 days.

30-3 = 27 days NO rain

7 0

2 years ago

Read 2 more answers

Which equation is true for the value x = 15?

boyakko [2]

The third one because 2(15+5)=2(20)=40

4 0

3 years ago

Statistics??? Construct a 95% confidence interval for the population mean. Assume the population has a normal distribution. A sa

antiseptic1488 [7]

Given:
μ = $3120, population mean
σ = $677, population standard deviation.
The population is normally distributed.
n = 20, sample size.

At the 95% confidence level, the confidence interval is
$( \mu - 1.96\frac{\sigma}{ \sqrt{n} } ,\, \mu + 1.96\frac{\sigma}{ \sqrt{n} })$

1.96(σ/√n) = 1.96(677/√20) = 296.71
Th confidence interval for the mean is
($2823.29, $3416.71)

Answer: ($2823.29, $3416.71)

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2 years ago