Answer:
0
Step-by-step explanation:
(-4,0) and (3,2)
m1=(2-0)/(3+4)=2/7
y=2/7x+b1, using point (-4,0) to find b1 (substitute x=-4 and y=0 in the form)
0=2/7*(-4)+b1 ⇒ b1= 8/7
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(-3,2) and (4,0)
m2=(0-2)/(4+3)= -2/7
y= -2/7x+b2, using point (4,0) to find b2 (substitute x=4 and y=0 in the form)
0= -2/7*4+b2 ⇒ b2=8/7
----
m1b2+m2b1= 2/7*8/7 -2/7*8/7=0
Answer:
see below
Step-by-step explanation:
A. Reflection across the y-axis replaces each x coordinate with its opposite.
B. Rotation 90° CW does the transformation (x, y) ⇒ (y, -x)
C. This is a translation left 2 units.
D. Rotation 90° CCW does the transformation (x, y) ⇒ (-y, x)
E. This is a translation left 7 and down 2.
__
In the attached graphs, we have identified a point that is a corresponding point on each figure. This is so you can see how the various transformations move it and the rest of the figure in relation to it. 90° arcs are shown so you can see the rotations more easily.
The figures are labeled and color coded in accordance with the problem statement.
Answer:
The probability that a performance evaluation will include at least one plant outside the United States is 0.836.
Step-by-step explanation:
Total plants = 11
Domestic plants = 7
Outside the US plants = 4
Suppose X is the number of plants outside the US which are selected for the performance evaluation. We need to compute the probability that at least 1 out of the 4 plants selected are outside the United States i.e. P(X≥1). To compute this, we will use the binomial distribution formula:
P(X=x) = ⁿCₓ pˣ qⁿ⁻ˣ
where n = total no. of trials
x = no. of successful trials
p = probability of success
q = probability of failure
Here we have n=4, p=4/11 and q=7/11
P(X≥1) = 1 - P(X<1)
= 1 - P(X=0)
= 1 - ⁴C₀ * (4/11)⁰ * (7/11)⁴⁻⁰
= 1 - 0.16399
P(X≥1) = 0.836
The probability that a performance evaluation will include at least one plant outside the United States is 0.836.
Answer:
0.3875
Step-by-step explanation:
Given that in a group of college students, the ratio of men to women is 3:1 (i.e., 3 to 1). In a recent survey, 40% of the men in this group selected hiking as their favorite outdoor activity whereas 35% of the women in the group selected hiking as their favorite outdoor activity
From the above information we find that
P(Men) = 0.75 and P(women) = 0.25 (since men:women = 3:1)
Out of men prob for not selecting hiking as their favorite outdoor activity

Out of women prob for not selecting hiking as their favorite outdoor activity

Prob for a randomly selected person that hiking is not his/her favorite outdoor activity = Prob (man and not selected activitiy) + P(women and not selected activity) (since men and women are mutually exclusive and exhaustive)
=