Question

Mason plays a game by flipping two fair coins.He wins the game if both coins land facing heads up. If Mason plays 200 times, how many times should he expect to win? Explain .

Answer 1

Answer:

Therefore Mason would be expected to win 50 times.

Step-by-step explanation:

i) probability of flipping a head for a fair coin is $\frac{1}{2}$

ii) probability of flipping two fair coins is = $\frac{1}{2} \times \frac{1}{2} = \frac{1}{4}$

iii) Therefore if Mason plays 200 times he would be expected to win

    = $\frac{1}{4} \times 200 = 50\hspace{0.1cm} times.$