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joja [24]
3 years ago
6

Wasani was playing Jeopardy. In this game of Jeopardy, players earn 50 points for a correct response and lose 50 points for an i

ncorrect response. So far, Wasani has answered 4 questions and his score is 0. Which of the following could be true?
Mathematics
2 answers:
nata0808 [166]3 years ago
6 0

Answer:

he answered 2 right and 2 wrong

Step-by-step explanation:

all you have to do is say 50+50 is 100 then he had he lost 50 points which would put him back to 0 so how much points would he lose if he answered 4 questions well 100

Nady [450]3 years ago
5 0
He got two correct and two wrong.
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An alarming number of U.S. adults are either overweight or obese. The distinction between overweight and obese is made on the ba
madreJ [45]

Answer:

(A) The probability that a randomly selected adult is either overweight or obese is 0.688.

(B) The probability that a randomly selected adult is neither overweight nor obese is 0.312.

(C) The events "overweight" and "obese" exhaustive.

(D) The events "overweight" and "obese" mutually exclusive.

Step-by-step explanation:

Denote the events as follows:

<em>X</em> = a person is overweight

<em>Y</em> = a person is obese.

The information provided is:

A person is overweight if they have BMI 25 or more but below 30.

A person is obese if they have BMI 30 or more.

P (X) = 0.331

P (Y) = 0.357

(A)

The events of a person being overweight or obese cannot occur together.

Since if a person is overweight they have (25 ≤ BMI < 30) and if they are obese they have BMI ≥ 30.

So, P (X ∩ Y) = 0.

Compute the probability that a randomly selected adult is either overweight or obese as follows:

P(X\cup Y)=P(X)+P(Y)-P(X\cap Y)\\=0.331+0.357-0\\=0.688

Thus, the probability that a randomly selected adult is either overweight or obese is 0.688.

(B)

Commute the probability that a randomly selected adult is neither overweight nor obese as follows:

P(X^{c}\cup Y^{c})=1-P(X\cup Y)\\=1-0.688\\=0.312

Thus, the probability that a randomly selected adult is neither overweight nor obese is 0.312.

(C)

If two events cannot occur together, but they form a sample space when combined are known as exhaustive events.

For example, flip of coin. On a flip of a coin, the flip turns as either Heads or Tails but never both. But together the event of getting a Heads and Tails form a sample space of a single flip of a coin.

In this case also, together the event of a person being overweight or obese forms a sample space of people who are heavier in general.

Thus, the events "overweight" and "obese" exhaustive.

(D)

Mutually exclusive events are those events that cannot occur at the same time.

The events of a person being overweight and obese are mutually exclusive.

5 0
3 years ago
Marina spent $13.50 at the grocery store. She bought pears, kiwis, and pineapples. Pears cost $0.50 each, pineapples cost $1.50
kiruha [24]

Answer:

Number of pineapples = 10

Number of pears = 10 + 9 = 19

Number of kiwis = 10 - 2 = 8

Step-by-step explanation:

Money = $ 13.5

Cost of a pear = $ 0.5

Cost of a pineapple = $ 1.5

Cost of a kiwi = $ 0.3

let the number of pineapple = p  

Number of pears = p + 9

Number of kiwis = p - 2

Cost is

0.5 (p + 9) + 0.15 p + 0.3 (p - 2) = 13.5

0.5 p + 4.5 + 0.15 p + 0.3 p - 0.6 = 13.5  

0.95 p = 9.6

p = 10

So, number of pineapples = 10

Number of pears = 10 + 9 = 19

Number of kiwis = 10 - 2 = 8  

4 0
3 years ago
Read 2 more answers
What is In algebraic expression
IgorLugansk [536]

Expression without an equal sign with at least one variable

Hope this helps!

5 0
3 years ago
Please help, i’ll mark brainliest.
nalin [4]

Answer:

264 cu

Step-by-step explanation:

This is because you have to add it from all sides, the first prism is 144 cu and then the second one is, 120, and when you add both of those together you get 264

<u><em>Thus the answer is....264</em></u>

5 0
3 years ago
What is (-1, 4) (1,-4) in y=mx form?
Anna35 [415]
Y=-4x+0 or just Y=-4x
8 0
3 years ago
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