You'll need to calculate the applicable z-score:
(given value of x) - (mean value)
z = -----------------------------------------------
standard deviation
370-400 -30
Here, z = --------------- = ---------- = -0.3
100 100
Use either a table of z scores or your calculator to determine the area under the standard normal curve to the left of z = -0.3.
According to my TI-83 Plus calculator, this area is 0.382.
The probability of selecting at random a score less than or equal to 370 is 0.382.
Answer:
Step-by-step explanation:
we know that
The exponential decay function that represent the depreciated value of the car is given by
where
y is the depreciated value of the car
t is the number of years since 2008
What is the approximate value of the car in 2012?
Find the value of t
substitute in the equation
Answer:98800
Step-by-step explanation:
Vertex form; y = 5(x - 3)² - 85
x-intercept; (3, +√17, 0) , (3 -√17, 0)
y-intercept; (0, -40)
minimum value at -85
range; [-85, ∞), {y|y ≥ -85}
hope this helps, God bless!
(1 point) Consider the universal set U={1,2,3,4,5,6,7,8,9,10}, define the set A be the even numbers, the set B be the odd number
Sloan [31]
Answer:
a) AUC = {2,4,6,8,10}
b) BnC = {}
c) AnB = {}
d) B-C = B = {1,3,5,7,9}
Step-by-step explanation:
The set A is the even numbers, those that are divisible by two.
So A = {2,4,6,8,10}
B is the odd numbe.rs. An odd number is a number that is not divisible by two.
So B = {1,3,5,7,9}.
C = {4,5,6}, as the problem states
a) The union of sets is a set containing all elements that are in at least one of the sets. So the union of A and C is a set that contains all elements that are in at least one of A or C.
So AUC = {2,4,6,8,10}.
b) The intersection of two sets consists of all elements that in both sets. So, the intersection of B and C is the set that contains all elements that are in both B and C.
There are no elements that are in both B and C, so the intersection is an empty set
BnC = {}
c) Same explanation as b), there are no elements that are in both A and B, so another empty set.
AnB = {}
d) The difference of sets B and C consists of all elements that are in B and not in C. We already have in b) that BnC = {}, so:
B-C = B = {1,3,5,7,9}
