So we have the system of equations:

equation (1)

equation (2)
To use substitution, we are going to solve for one variable in one of our equations, and then we are going to replace that value in the other equation:
Solving for

in equation (2):



equation (3)
Replacing equation (3) in equation (1):






equation (4)
Replacing equation (4) in equation (3):



We can conclude that the solution of our system of equations is <span>
(7/5, 21/10)</span>
Answer:
6x-5y=4
6x+3y=30
Step-by-step explanation:
Move variable to the left
5y=6x-4
Reorder the terms
5y-6x=-4
Change the signs
-6x+5y=-4
Move variable to the left
3y=-6x+20
Reorder the terms
3y+6x=20
You are taking off 8 each 2 at x, so it would be four for each 1 at x. therefore 2 is 9, 1 is 13 and...
the value of y is 17 when x = 0
sorry if i explained that bad
hence the answer for the question is 1 and 4