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BartSMP [9]
3 years ago
6

What is the distance between the sandbox and garden

Mathematics
1 answer:
elena55 [62]3 years ago
6 0
For this case, the first thing we must do is apply the law of the sine.
 We then have the following expression:
 sine (65) / x = sine (104) / 36
 Clearing the value of x we have:
 x = (sine (65) / sine (104)) * (36)
 x = 33.6 feet
 Answer:
 
The distance between the sandbox and garden is:
 
x = 33.6 feet
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Answer 10$ + 8$+5$= answer that first.

Step-by-step explanation:

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EastWind [94]
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3 years ago
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5 0
4 years ago
Consider the two data sets below:
alina1380 [7]

Answer:

<u><em>Option c) The data sets will have the same values of their interquartile range.</em></u>

<u><em></em></u>

Explanation:

<u>1. The values are in order: </u>they are in increasing oder, from lowest to highest value.

<u>2. Calculate the interquartile range.</u>

<em />

<em>Interquartile range</em>, IQR, is the third quartile, Q3, less the first quartile Q1:

  • IQR = Q3 - Q1

To find the first and the third quartile, first find the median:

<u>Data Set 1</u>: 19, 25, 35, 38, 41, 49, 50, 52, 59

             [19, 25, 35, 38],  41,  [49, 50, 52, 59]

                                         ↑

                                     median = 41

   

<u>Data Set 2</u>: 19, 25, 35, 38, 41, 49, 50, 52, 99

             [19, 25, 35, 38] , 41,  [49, 50, 52, 99]

                                         ↑

                                      median = 41

Now find the median of each subset: the values below the median and the values above the median.

Data set 1: <u>First quartile</u>

                [19, 25, 35, 38],

                            ↑

                           Q1 = [25 + 35] / 2 = 30

                   <u>Third quartile</u>

                   [49, 50, 52, 59]

                                ↑

                                Q3 = [50 + 52] / 2 = 51

                     IQR = Q3 - Q1 = 51 - 30 = 21

Data set 2: <u> First quartile</u>

                   [19, 25, 35, 38]

                               ↑

                               Q1 = [25 + 35] / 2= 30

                  <u>Third quartile</u>

                   [49, 50, 52, 99]

                                ↑

                                Q3 = [52 + 50]/2 = 51

                   IQR = 51 - 30 = 21

Thus, it is shown that the data sets have will have the same values for the interquartile range: IQR = 21. (option c)

This happens because replacing one extreme value (in this case the maximum value) by other extreme value does not affect the median.

<em>An outlier will change the range</em> because the range is the maximum value less the minimum value.

5 0
3 years ago
An above ground swimming pool in the shape of a cylinder has a diameter of 21 feet and a height of 3.5 feet. If the pool is fill
svlad2 [7]

Answer:

952 cubic feet

Step-by-step explanation:

The diameter is 21, so the radius is 10.5. The area of a circle is πr^2, so 10.5^2π, or 110.25π. The pool is filled 9 inches from the top, so it is 3.5 feet - 9 inches high, 9 inches is 0.75 feet, so 2.75 feet filled. Now multiply 110.25π by 2.75 to get 303.1875π and then 952.4916, closer to 952 cubic feet.

Tell me if I'm right

3 0
3 years ago
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