Answer:
a) 33.33%)
b) 135 minutes
c) 8.66 min
d) 50%
Step-by-step explanation:
a) the probability for a uniform distribution is
P(b<X<a) = (a-b)/(c-d) , where c and d are the maximum and minimum values
therefore the probability that the flight is more than 140 minutes ( and less than 150 since it is the maximum value)
P(140<X<150) = (a-b)/(c-d) = (150-140)/(150-120) = 10/30 = 1/3 (33.33%)
b) the mean (expected value) for a uniform probability distribution is
E(X) = (c+d)/2 = (120+150)/2 = 135 minutes
c) the standard deviation for a uniform probability distribution is
σ²(X)= (c-d)²/12 = (150-120)²/12 = 75 min²
σ = √75 min² = 8.66 min
b) following the same procedure as in a)
P(120<X<135) = (a-b)/(c-d) = (135-120)/(150-120) = 15/30 = 1/2 (50%)
Answer:
The relation represents a growth when b>1 and a decay when 0<b<1
Step-by-step explanation:
Any function in the form 
, where a > 0, b > 0 and b not equal to 1 is called an exponential function with base b. If 0 < b < 1. It is an example of an exponential decay. The general shape of an exponential with b > 1 is an example of exponential growth. An exponential function is expressed in the form 
The relation represents a growth when b >1 and a decay when 0<b<1.
Answer:
7846
Step-by-step explanation:
two 'minus' signs cancel each other out and become an 'plus' sign
therefore
7512-(-334) = 7512 + 334
= 7846
I don't know why you wrote ' write your answer as a 'mixed number ' in 'simplest form'. A mixed number can only be formed when you have a fraction, an improper fraction no less, the answer is a whole number, and therefore cannot be written as a mixed number in simplest form. If I am wrong pls let me know and elaborate by what you mean by 'mixed number' in the comments.
I believe it may be a trick question, but who knows.
Examples of fractions expressed as a mixed number.
19/8 = 2 3/8
17/5 = 3 2/5
Zero on number lines is neither negative nor positive, it is used as a sort of divider number;)
Step-by-step explanation: this picture should help explain a little
I believe it is option choice A, because that is the most reasonable and efficient
