Iterations question two need help please :)
1 answer:
Answer:
option b
1 , 16, 121 , 13456
Step-by-step explanation:
Given in the question a function, f(x) = (x - 5)²
initial value = 4
First iteration
f(x0) = f(4) = (4 - 5)² = (-1)² = 1
x1 = 1
Second iteration
f(x1) = f(1) = (1 - 5)² = (-4)² = 16
x2 = 16
Third iteration
f(x2) = f(16) = ( 16 - 5)² = (11)² = 121
x3 = 121
Fourth iteration
f(x3) = f(121) = (121 - 5)² = (116)² = 13456
x4 = 13456
You might be interested in
<u>Answer-</u>
a. Probability that three of the candies are white = 0.29
b. Probability that three are white, 2 are tan, 1 is pink, 1 is yellow, and 2 are green = 0.006
<u>Solution-</u>
There are 19 white candies, out off which we have to choose 3.
The number of ways we can do the same process =
As we have to draw total of 9 candies, after 3 white candies we left with 9-3 = 6, candies. And those 6 candies have to be selected from 52-19 = 33 candies, (as we are drawing candies other than white, so it is subtracted)
And this process can be done in,
So total number of selection = (969)×(1107568) = 1073233392
Drawing 9 candies out of 52 candies,
∴P(3 white candies) =
Total number of ways of selecting 3 whites, 2 are tans, 1 is pink, 1 is yellow, and 2 are greens is,
Total number of selection = 3 whites + 2 are tans + 1 is pink + 1 is yellow + 2 greens = 9 candies out of 52 candies is,
∴ P( 3 whites, 2 are tans, 1 is pink, 1 is yellow, 2 greens) =