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3 years ago

Please help me.

Mathematics

2 answers:

Svetllana [295]3 years ago

4 0

Answer:

jdjdjdjd

Step-by-step explanation:

9999999

Bess [88]3 years ago

4 0

Answer:

I play football

Step-by-step explanation:

I play football

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Cole has 5 times as many pencils as

Nataly [62]

Answer:

Cole has 15 pencils.

Step-by-step explanation:

First, we have the equation c + o =18, c representing cole, and o representing connor.

From there, we get 5o=c

Using substitiution, we get o=3

5(3)=15

15+3=18

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2 years ago

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Kazeer [188]

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2 years ago

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Marcello is constructing the perpendicular bisector of AB. He has already constructed arcs as shown.

Andrews [41]

Did u get the answer please help me i am taking the test right now?!

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3 years ago

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8.46 If 100 is decreased by a% and the result is decreased by b%, then what is the total percent decrease (in terms of a and b)?

Marysya12 [62]

Answer:

The total percent decrease is $a+b-\frac{a b}{100}$

Step-by-step explanation:

We are given with a word problem
We are asked to find the total percentage decrease
We can do this in two steps

Step 1: Finding the two percentage decrease

Step 2: Finding their difference

Step 1 of 2

Let the decrease by a% be 100-a

Then b% decrease is

$\begin{aligned}\frac{b}{100} \times(100-a) &=\frac{100 b-a b}{100} \\\frac{100 b}{100}-\frac{a b}{100} &=b-\frac{a b}{100}\end{aligned}$

Step 2 of 2

The percentage difference between the two percentages is,

$\begin{aligned}&(100-a)-\left(b-\frac{a b}{100}\right)=100-a-b+\frac{a b}{100} \\&100-a-b+\frac{a b}{100}=100-\left(a+b-\frac{a b}{100}\right)\end{aligned}$

Since 100 is the total percent $a+b-\frac{a b}{100}$ is the percentage decrease.

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1 year ago

In a chess club the probability that Shaun will beat Mike is 3/8 .

romanna [79]

Answer:

$\frac{10}{56} = 0.1786$ probability that Shaun loses both games

Step-by-step explanation:

Games are independent, so we find each separate probability, and multiply them.

In a chess club the probability that Shaun will beat Mike is 3/8.

So $1 - \frac{3}{8} = \frac{8}{8} - \frac{3}{8} = \frac{5}{8}$ probability that Shaun loses.

The probability that Shaun will beat Tim is 5/7 .

So $1 - \frac{5}{7} = \frac{2}{7}$ probability that Shaun loses.

What is the probability that Shaun loses both games?

This is:

$p = \frac{5}{8} \times \frac{2}{7} = \frac{5*2}{8*7} = \frac{10}{56} = 0.1786$

$\frac{10}{56} = 0.1786$ probability that Shaun loses both games

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3 years ago