12y-2
-6p+2.5
-18+1.75r
-20b+2.4
Answer:
d. 1
Step-by-step explanation:
The base for this "exponential" function is sufficiently close to 1 that the function looks linear. The value corresponding to x=0 seems to be 1.00. Rounded to tenths, it is 1.0.
May be there is an operator missing in the first function, h(x). I will solve this in two ways, 1) as if the h(x) = 5x and 2) as if h(x) = 5 + x
1) If h(x) = 5x and k(x) = 1/x
Then (k o h) (x) = k ( h(x) ) = k(5x) = 1/(5x)
2) If h(x) = 5 + x and k (x) = 1/x
Then (k o h)(x) =k ( h(x) ) = k (5+x) = 1 / [5 + x]
125 cubes can be made up with 18 cubes how? multiply 5×5×5 witch gets you 125.
hope that helps
(pemdas), parenthesis then exponents.
7 * 2 = 14
14^ 7 = 105413504
