Question

Write the first four terms of the sequence. f(n) = (n-1) (n-2)

Answer 1

Answer:

the first four terms are 0,0,2,6

Step-by-step explanation:

The computation of the first four terms of the sequence is shown below:

Given that

f(n) = (n - 1) (n -2)

= n^2 - 2n - n + 2

= n^2 - 3n + 2

Now the first four terms are

f(1) = 1^2 - 3(1) + 2

= 1 - 3 + 2

= 0

f(2) = 2^2 - 3(2) + 2

= 4 -6 + 2

= 0

f(3) = 3^2 - 3(3) + 2

= 9 - 9 + 2

= 2

f(4) = 4^2 - 3(4) + 2

= 16 - 12 + 2

= 18 - 12

= 6

So, the first four terms are 0,0,2,6