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AlexFokin [52]
3 years ago
12

How to draw perpendicular line to a line through given point

Mathematics
1 answer:
Goshia [24]3 years ago
5 0
Go to www.khanaccedmy.com, that will help you.
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What’s a simple definition of the term Covalent Bond?
weeeeeb [17]

Answer:

A chemical bond that involves the sharing of electron pairs between atoms.

Step-by-step explanation:

7 0
3 years ago
90 is what percent of 270
erik [133]

Answer:

33 \frac{1}{3}%

Step-by-step explanation:

Create a fraction where the of value is on the denominator, then multiply by 100% to change to a percentage, that is

\frac{90}{270} ×100%

= 33.3333... × 100% = 33.333... % = 33 \frac{1}{3}% ← exact value



4 0
4 years ago
The equation sin (40)= b/20 can be used to determine the length of line segment AC.
Furkat [3]
Provided that the triangle looks like this:

A| \  |   \  |    \  |     \  |      \ b|        \   20  |           \  |              \  |                \  |                 \  |_______40\C      a          B

Then using the the equation to solve for line segment AC (or b on the diagram):

sin(40) = b/20

b = 20 * sin 40
b = segment AC = 12.9 units
8 0
4 years ago
Read 2 more answers
The price of a technology stock has risen to $9.73 today. Yesterday's price was $9.60 . Find the percentage increase. Round your
Daniel [21]
Hello! To find this answer, we have to do change/original. 9.73 - 9.60= 0.13. 0.13/9.60 = 0.01354 and other numbers behind it or 1.4% when rounded to the nearest tenth. You have to multiply the decimal by 100 in order to to get the percent form. It rounds up to 1.4 instead of back down to 1.3, because the 5 is in the hundredths place, and when anything 5 or more appears behind the digit you are rounding to, you go up. The percent increase is about 1.4%.
4 0
4 years ago
HELP!!<br> let g(x)=5x-2 and h(x)= x^2 +1. Find (h o g) (-1)
frosja888 [35]

Answer:

(h o g)(-1))  = 50

Step-by-step explanation:

Here, the functions are defined as

g(x) = 5x -2

h(x)  = x^{2}  + 1

Now, (h 0 g) (x) is defined as the function h of g(x).

⇒  (h 0 g) (x) = h(g(x))

now, by definition of both functions:

h(g(x))  = h(5x-2)  = (5x-2)^{2}  + 1

⇒h(g(x))  = (25x^{2}  + 4 - 20x)+ 1 = 25x^{2}  + 5 - 20x

Putting x = -1 in the above expression,

h(g(-1))  = 25(-1)^{2}  + 5 - 20(-1)\\= 25 + 5 + 20= 50

Hence, h(g(-1))  = 50 or

(h o g)(-1))  = 50

6 0
4 years ago
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