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iren2701 [21]
3 years ago
10

Find the value of 15.0 N in pounds. Use the conversions 1slug=14.59kg and 1ft=0.3048m .

Mathematics
1 answer:
Sliva [168]3 years ago
6 0

The value of 15.0 N in pounds = 3.375 lb

<h3><em>Further explanation </em></h3>

The derivative magnitude is a quantity derived from the principal amount

7 main quantities have been determined based on international standards, namely:

  • 1. Length, meters (m)
  • 2. Time, second (s)
  • 3. Mass, kilograms (kg)
  • 4. Temperature, kelvin (K)
  • 5. Light intensity, candela (cd)
  • 6. Electric current, ampere (A)
  • 7. Amount of substance, mol (m)

Newton (N) is one unit of force (F) which is a quantity derived from mass (m), length (l) and time (s)

Newton can be expressed in terms of Kg m / s²

Formula used:

F = m. a

N = kg. m / s²

In the British system there are units of slug, feet, and pounds so that the unit of force becomes:

F = m. a

Lb = slug. ft / s²

The relationship between the two-unit systems above is:

1 kg = 0.0685 slug

1 slug = 14.59 kg

1 newton = 0.225 lb

1 lb = 4,448 newtons

1 ft = 0.3048 m

So if we change 15 N to lb by using slug and ft

15 N = 15 * (1 / 14.59) slug * (1 / 0.3048) ft / s²

15 N = 3,375 slug ft / s ²

15 N = 3,375 lb

or we convert directly:

15 N = 15 * 0.225 lb

15 N = 3,375 lb

<h3><em>Learn more </em></h3>

yard conversion

brainly.com/question/2479097

the quantity 0.0075 meters expressed in centimeters

brainly.com/question/2867118

A vineyard has 145 acres of Chardonnay grapes

brainly.com/question/982615

Keywords: slug, Newton, feet, kg, pound

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maw [93]

Answer:

(1) The expected number of people who would have consumed alcoholic beverages is 34.9.

(2) The standard deviation of people who would have consumed alcoholic beverages is 10.56.

(3) It is surprising that there were 45 or more people who have consumed alcoholic beverages.

Step-by-step explanation:

Let <em>X</em> = number of adults between 18 to 20 years consumed alcoholic beverages in 2008.

The probability of the random variable <em>X</em> is, <em>p</em> = 0.697.

A random sample of <em>n</em> = 50 adults in the age group 18 - 20 years is selected.

An adult, in the age group 18 - 20 years, consuming alcohol is independent of the others.

The random variable <em>X</em> follows a Binomial distribution with parameters <em>n</em> = 50 and <em>p</em> = 0.697.

The probability mass function of a Binomial random variable <em>X</em> is:

P(X=x)={50\choose x}0.697^{x}(1-0.697)^{50-x};\ x=0,1,2,3...

(1)

Compute the expected value of <em>X</em> as follows:

E(X)=np\\=50\times 0.697\\=34.85\\\approx34.9

Thus, the expected number of people who would have consumed alcoholic beverages is 34.9.

(2)

Compute the standard deviation of <em>X</em> as follows:

SD(X)=\sqrt{np(1-p)}=\sqrt{50\times 0.697\times (1-0.697)}=10.55955\approx10.56

Thus, the standard deviation of people who would have consumed alcoholic beverages is 10.56.

(3)

Compute the probability of <em>X</em> ≥ 45 as follows:

P (<em>X</em> ≥ 45) = P (X = 45) + P (X = 46) + ... + P (X = 50)

                =\sum\limits^{50}_{x=45} {50\choose x}0.697^{x}(1-0.697)^{50-x}\\=0.0005+0.0001+0.00002+0.000003+0+0\\=0.000623\\\approx0.0006

The probability that 45 or more have consumed alcoholic beverages is 0.0006.

An unusual or surprising event is an event that has a very low probability of success, i.e. <em>p</em> < 0.05.

The probability of 45 or more have consumed alcoholic beverages is 0.0006. This probability value is very small.

Thus, it is surprising that there were 45 or more people who have consumed alcoholic beverages.

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