" · " - times
" + " - sum
n - a number
0.5n - half a number
10 · (0.5n + 6) = 8 |use distributive property
(10)(0.5n) + (10)(6) = 8
5n + 60 = 8 |substract 60 from both sides
5n = -52 |divide both sides by 5
n = -10.4
The coordinates of the midpoint are just the average of the endpoint coordinates ...
x-mid is the average of the end-x's, and y-mid is the average of the end-y's.
P. x = 0, y = 8
Q. x = 4, y = 2
'x' of the midpoint is the average of 0 and 4 = (1/2)(0 + 4) = 2
'y' of the midpoint is the average of 8 and 2 = (1/2)(8 + 2) = 5
The midpoint is (2, 5) .
That's choice-'c'.
Problem 2
<h3>Answers:</h3><h3>Domain = [-2, 2)</h3><h3>Range = {-2, -1, 0, 1, 2}</h3>
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Explanation:
The domain is the set of allowed x inputs of a function. We see that the left most point is when x = -2, so -2 is the smallest value allowed in the domain. On the opposite side of the spectrum, we see that x = 2 is the right most value. However, x = 2 is not allowed in the domain because of the open hole here. This is why we use a curved parenthesis for this part. Whereas a square bracket for -2 tells the reader "-2 is part of the domain". The answer you wrote down is very close. Just change the second square bracket to a curved parenthesis.
For the range, we simply have 5 possible y value outputs and they are: -2 -1, 0, 1 or 2. No other y values are possible. Since we have so few items in the range, we just list the values and put them between curly braces to indicate we have a set of values. We cannot do this with the domain as there are infinitely many items in the domain (eg: x = 1.27 and x = 2.339 are in the domain).
So you subtract the five over to get -5=2e^z, divide by 2, -2.5=e^z, take the natural log of both sides to get z=ln(-2.5) which does not exist
Answer:
17/45
Step-by-step explanation:
