Answer:
The answer is
<h2>32.4 g</h2>
Explanation:
The mass of a substance when given the density and volume can be found by using the formula
<h3>mass = Density × volume</h3>
From the question
volume of aluminum = 12 cm³
Density = 2.70 g/cm³
The mass of aluminum is
mass = 2.7 × 12
We have the final answer as
<h3>32.4 g</h3>
Hope this helps you
Answer:
It has two sigma bonds ( the single bonds between each H and C) plus one pi bond and one sigma bond that consitute the double bond between C and O. It contains three covalent bonds, one . Hydrogen Bond Donor Count: 0: Computed by Cactvs 3.4.
Explanation:
Hope it helps you!
The correct answer would be 2
Answer:
26.56g
Explanation:
The half life of an isotope decay is the time transcurred when the initial amount of the isotope decays to the half of its amount.
For the problem, when 1 half life transcur, the sample has a mass of:
425g / 2 = 212.5g
When 2 half lives transcur:
212.5g / 2 = 106.25g
3 half lives:
106.25/2 = 53.13g
And the amount that is found after 4 half lives is:
53.13/2 =
<h3>26.56g</h3>
Answer:
it is possible to remove 99.99% Cu2 by converting it to Cu(s)
Explanation:
So, from the question/problem above we are given the following ionic or REDOX equations of reactions;
Cu2+ + 2e- <--------------------------------------------------------------> Cu (s) Eo= 0.339 V
Sn2+ + 2e- <---------------------------------------------------------------> Sn (s) Eo= -0.141 V
In order to convert 99.99% Cu2 into Cu(s), the equation of reaction given below is needed:
Cu²⁺ + Sn ----------------------------------------------------------------------------> Cu + Sn²⁺.
Therefore, E°[overall] = 0.339 - [-0.141] = 0.48 V.
Therefore, the change in Gibbs' free energy, ΔG° = - nFE°. Where E° = O.48V, n= 2 and F = 96500 C.
Thus, ΔG° = - 92640.
This is less than zero[0]. Therefore, it is possible to remove 99.99% Cu2 by converting it to Cu(s) because the reaction is a spontaneous reaction.
