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tia_tia [17]
3 years ago
6

Consider the reaction pathway graph below.

Chemistry
1 answer:
san4es73 [151]3 years ago
6 0
Hello!

If the reaction could be made to go faster B. The hill would be shorter.

The "hill" is called Activation Energy. It is the energy of the activated intermediate compound needed to complete the reaction. Catalysts are substances that don't intervene in the reaction which speed up the rate of a given reaction by lowering the Activation Energy giving alternate reaction pathways with lower-energy intermediates. If the reaction could be made to go faster with the use of a catalyst, then the Activation Energy would be lower and the "hill" would be shorter.

Have a nice day!
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How much heat would be released by 1.3 kg of water if it's temperature went from 295 k to 274 k
kicyunya [14]

Answer: The energy released will be 114.223 kJ.

Explanation:

To calculate the amount of heat released, we use the formula:

Q= m\times c\times \Delta T

Q = heat gained  or released

m = mass of the substance = 1.3kg = 1300 g   (Conversion factor: 1kg = 1000g)

c = heat capacity of water = 4.184 J/g K

\Delta T={\text{Change in temperature}}=(274-295)K=-21K

Putting values in above equation, we get:  

Q=1300g\times 4.184J/gK\times (-21)K

Q = -114223 Joules  = -114.223 kJ      (Conversion Factor: 1kJ = 1000J)

Negative sign implies heat released.

Hence, heat released by 1.3 kg of water is 114.223kJ.

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3 years ago
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Licemer1 [7]
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8 0
4 years ago
What is the percent composition of C4H10? (4 points)
Marina CMI [18]

Answer:82.7% C and 17.3% H

Explanation:

C4 = 12.0107g/mol x 4 = 48.0428 g/mol

H10 = 1.00794 g/mol x 10 = 10.0794 g/mol

Molar Mass of Butane, C4H10 =  48.0428 g/mol + 10.0794 g/mol= 58.1222 g/mol

percent composition of Carbon is  = ( mass of carbon contained in butane / molar mass of Butane) x 100

=(48.0428 /58.1222) x 100% = 0.8265 x 100

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( 10.0794/58.122 ) x 100% =0.1734 x 100

= 17.3% OF Hydrogen.

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denis23 [38]
PV = nRT
P is pressure, V is volume in L, n is number of moles, R is the gas constant, and T is temperature in K

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n = .5 moles x 38 grams per mol F2 = 19.4 grams F2
8 0
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Answer:

Please see the attached picture for the complete answer.

Explanation:

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