Answer: The energy released will be 114.223 kJ.
Explanation:
To calculate the amount of heat released, we use the formula:

Q = heat gained or released
m = mass of the substance = 1.3kg = 1300 g (Conversion factor: 1kg = 1000g)
c = heat capacity of water = 4.184 J/g K

Putting values in above equation, we get:

Q = -114223 Joules = -114.223 kJ (Conversion Factor: 1kJ = 1000J)
Negative sign implies heat released.
Hence, heat released by 1.3 kg of water is 114.223kJ.
I think it is space or displacement
Answer:82.7% C and 17.3% H
Explanation:
C4 = 12.0107g/mol x 4 = 48.0428 g/mol
H10 = 1.00794 g/mol x 10 = 10.0794 g/mol
Molar Mass of Butane, C4H10 = 48.0428 g/mol + 10.0794 g/mol= 58.1222 g/mol
percent composition of Carbon is = ( mass of carbon contained in butane / molar mass of Butane) x 100
=(48.0428 /58.1222) x 100% = 0.8265 x 100
=82.65% =82.7% of Carbon.
Percent composition of Hydrogen = (mass of Hydrogen contained in Butane / molar mass of Butane )x 100
( 10.0794/58.122 ) x 100% =0.1734 x 100
= 17.3% OF Hydrogen.
PV = nRT
P is pressure, V is volume in L, n is number of moles, R is the gas constant, and T is temperature in K
(1.23 atm)(10.3 L) = (n)(.08206)(29.8 + 273)
n = .5 moles x 38 grams per mol F2 = 19.4 grams F2
Answer:
Please see the attached picture for the complete answer.
Explanation: