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Nutka1998 [239]
2 years ago
11

The drama club is selling tickets to their play to raise money for the show's expenses. They are selling both adult tickets and

student tickets. The auditorium can hold no more than 100 people. Write an inequality that could represent the possible values for the number of student tickets sold, ss, and the number of adult tickets sold, aa, that would satisfy the constraint.
Mathematics
1 answer:
tensa zangetsu [6.8K]2 years ago
5 0

Answer:

Step-by-step explanation:

0 ≤ aa+ss ≤ 100

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A priter charges $2.85 for binding plus 10 cents per pages for each copy of a community group's annual report. If the report cos
UNO [17]

Answer:30 pages

Step-by-step explanation:

Starting with 2.85, if each copy costs 10 cents then 5.85-2.85=3. You have 3 dollars left until reaching 5.85. 30 pages would cost 300 cents or 3 dollars.

7 0
3 years ago
What is the value of the expression 6( -5 1/4 ?
Norma-Jean [14]

Answer:

-63/2

Step-by-step explanation:

6( -5  1/4)

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= -63/2

6 0
2 years ago
Erica is a sheep farmer. She is having a problem with wolves attacking the flock. She starts with an initial 200 sheep and notic
Free_Kalibri [48]

The equation for the situation is y=200(\frac{2}{3})^{x}

It will take around 9 years for her to have around 5 sheep

Step-by-step explanation:

The exponential decay growth/decay equation is y=a(b)^{x} , where

  • a is the initial value
  • b is the growth/decay factor
  • If b > 1, then it is a growth factor
  • If 0 < b < 1, then it is a decay factor

Erica is a sheep farmer. She is having a problem with wolves attacking the flock. She starts with an initial 200 sheep and notices that the population is two-thirds of the previous year

∵ The population is decreased

∴ The equation is decay

∵ The population is two-thirds of the previous year

∴ The decay factor is \frac{2}{3}

∵ She starts with an initial 200 sheep

∴ the initial value is 200

∵ The decay equation is y=a(b)^{x} , where y represent the

   population in x years

∵ a = 200

∵ b = \frac{2}{3}

∴ y=200(\frac{2}{3})^{x}

The equation for the situation is y=200(\frac{2}{3})^{x}

∵ The population after x years is around 5 sheep

- Substitute y by 5 to find x

∵ 5=200(\frac{2}{3})^{x}

- Divide both sides by 200

∴ 0.025=(\frac{2}{3})^{x}

- Insert ㏒ for both sides

∴ log(0.025)=log(\frac{2}{3})^{x}

∴ log(0.025)=xlog(\frac{2}{3})

- Divide both sides by log(\frac{2}{3})

∴ 9.098 = x

∴ x is around 9 years

It will take around 9 years for her to have around 5 sheep

Learn more:

You can learn more about the equation  in brainly.com/question/10666510

#LearnwithBrainly

8 0
3 years ago
Please help <br> add. 6 3/7 + 4 3/4 + 5 4/7
ratelena [41]
17 1/6
That is the answer
5 0
3 years ago
Read 2 more answers
one circle has a circumference of 12 pi . another circle has a circumference of 32 pi . what is the ratio of the radius of the s
SOVA2 [1]
<span>circumference=pi * 2 radius=12pi, radius(small)=6;
</span>circumference=pi * 2 <span>radius=32pi, radius(small)=16;</span>
6:16=3:8
6 0
3 years ago
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