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3 years ago

4 and 5? Plz?!?!?!?!?!?

Mathematics

1 answer:

masha68 [24]3 years ago

4 0

So (x,y), graph the number on the x axis thats in the x box, then go up the y axis the number of times it says for y in the correlating box.
for 5) lable the graph 0, 50, 100, 150, 200, 250, 400 on the y axis and try to graph the dot as close to the actual number as you can

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A sports store sells three different packs of tennis balls. Brand A costs $2.50 for two balls, brand B sells three balls for $3.

meriva

Answer:

Step-by-step explanation:

sports store sells three different packs of tennis balls. Brand A costs $2.50 for two balls, brand B sells three balls for $3.90, and brand C has a sale of four balls for $5.12. Which inequality about the unit price per ball is correct

Brand A:

$2.50 for 2

Brand B :

$3.90 for 3

Brand C:

$5.12 for 4

We calculate the unit price :

Brand A:

$2.50 / 2 = $1.25

Brand B:

$3.90 / 3 = $1.30

Brand C:

$5.12 / 4 = $1.2

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3 years ago

Find the distance between the points (1,3) and (5,0).

Irina18 [472]

distance between two points is [(x2-x1)^2 +(y2-y1)^2]^1/2

I.e,[{5-1)^2+(0-3)^2]^1/2

[16+9]^1/2

[25]^1/2

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3 years ago

What is 21% as a fraction

Kruka [31]

21/100 is a fraction form

6 0

3 years ago

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Expand the expression using the distributive property. 2(5x – 3)

riadik2000 [5.3K]

Answer:

10x-6

Step-by-step explanation:

4 0

3 years ago

I am offering another 100 points

Ivahew [28]

Answer:

$\sf Since \;\sqrt{\boxed{64}}=\boxed{8}\;and\;\sqrt{\boxed{81}}=\boxed{9}\; \textsf{it is known that $\sqrt{75}$ is between}\\\\\sf \boxed{8}\;and\;\boxed{9}\;.$

Step-by-step explanation:

Perfect squares: 4, 9, 16, 25, 36, 49, 64, 81, 100, 121, ...

To find $\sf \sqrt{75}$ , identify the perfect squares immediately before and after 75:

64 and 81

$\begin{aligned}\sf As\;\; 64 < 75 < 81\; & \implies \sf \sqrt{64} < \sqrt{75} < \sqrt{81}\\&\implies \sf \;\;\;\;\;8 < \sqrt{75} < 9 \end{aligned}$

$\sf Since \;\sqrt{\boxed{64}}=\boxed{8}\;and\;\sqrt{\boxed{81}}=\boxed{9}\; \textsf{it is known that $\sqrt{75}$ is between}\\\\\sf \boxed{8}\;and\;\boxed{9}\;.$

See the attachment for the correct placement of $\sf \sqrt{75}$ on the number line.

6 0

1 year ago

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