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2 years ago

Which of the following is a 1. repeating decimal? 1. 14/7 2. 9/6 3. 1/4 4. 5/9

Mathematics

1 answer:

Amanda [17]2 years ago

3 0

Answer:

9/6

Step-by-step explanation:

1/4 is less than 1, so its not 1. 5/9 is also less than 1, so its also not 1. 14 divided by 7 equals 2 so that is not 1. 9/6 is the only option left :)

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A gumball machine has different flavors sour apple,grape,orange and cherry . There are six of each flavor. $.50 are put in the m

tamaranim1 [39]

Answer:

30/552

Step-by-step explanation:

In order to solve this problem you need to multiply the probability of getting grape for the first gumball with the probability of getting grape for the second gumball. Since there are 6 grape gumballs and a total of 24 gumballs (6*4). Then the probability of getting grape for the firs one is

$\frac{6}{24}$

Now there are only 5 grape gumballs available and one less in the total supply, therefore the probability of getting grape in the second try is

$\frac{5}{23}$

Finally we multiply them together to find the probability of getting two grapes in a row.

$\frac{6*5}{24*23}$ = $\frac{30}{552}$

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2 years ago

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KonstantinChe [14]

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3 years ago

Iven right triangle XYZ, what is the value of tan(60°)?

gayaneshka [121]

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3 years ago

Read 2 more answers

) f) 1 + cot²a = cosec²a

notsponge [240]

Answer:

It is an identity, proved below.

Step-by-step explanation:

I assume you want to prove the identity. There are several ways to prove the identity but here I will prove using one of method.

First, we have to know what cot and cosec are. They both are the reciprocal of sin (cosec) and tan (cot).

$\displaystyle \large{\cot x=\frac{1}{\tan x}}\\\displaystyle \large{\csc x=\frac{1}{\sin x}}$

csc is mostly written which is cosec, first we have to write in 1/tan and 1/sin form.

$\displaystyle \large{1+(\frac{1}{\tan x})^2=(\frac{1}{\sin x})^2}\\\displaystyle \large{1+\frac{1}{\tan^2x}=\frac{1}{\sin^2x}}$

Another identity is:

$\displaystyle \large{\tan x=\frac{\sin x}{\cos x}}$

Therefore:

$\displaystyle \large{1+\frac{1}{(\frac{\sin x}{\cos x})^2}=\frac{1}{\sin^2x}}\\\displaystyle \large{1+\frac{1}{\frac{\sin^2x}{\cos^2x}}=\frac{1}{\sin^2x}}\\\displaystyle \large{1+\frac{\cos^2x}{\sin^2x}=\frac{1}{\sin^2x}}$

Now this is easier to prove because of same denominator, next step is to multiply 1 by sin^2x with denominator and numerator.

$\displaystyle \large{\frac{\sin^2x}{\sin^2x}+\frac{\cos^2x}{\sin^2x}=\frac{1}{\sin^2x}}\\\displaystyle \large{\frac{\sin^2x+\cos^2x}{\sin^2x}=\frac{1}{\sin^2x}$