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3 years ago

13+(x+8) plz i need help

Mathematics

2 answers:

Bas_tet [7]3 years ago

6 0

Answer:

21+x

Step-by-step explanation:

Because this does not equal anything, we can't solve for x. Instead, we can just simplify the equation. Since there is a + sign to the left of the parentheses, it shows that we do not need to distribute.

13+(x+8)

21+x

Hope this helps!! Have a nice day ^^

Dvinal [7]3 years ago

5 0

Answer:

First off you would distribute the invisible positive 1 to the x and 8

Then you will get 13+x+8

Last add 13 and 8 to get 21

Your final answer is 21+x

Step-by-step explanation:

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Factor the expression completely over the complex numbers.<br><br> x4−625

marusya05 [52]

Your factoring answer is: (x^2+25)(x+5)(x-5)

6 0

3 years ago

Sam takes out a $167,000 mortgage for 20 years. He makes monthly payments and at the end calculates

cupoosta [38]

Answer:

The Annual rate of interest for the mortgage is 1.8%

Step-by-step explanation:

Given as :

The mortgage principal = p = $167,000

The time period of mortgage = t = 20 years

The Amount paid towards mortgage in 20 years = A = $240,141

Let the Annual percentage rate on interest = r % compounded annually

Now, <u>From Compound Interest method</u>

Amount = Principal × $(1+\dfrac{\textrm rate}{100})^{\textrm time}$

Or, A = p × $(1+\dfrac{\textrm r}{100})^{\textrm t}$

Or, $240,141 = $167,000 × $(1+\dfrac{\textrm r}{100})^{\textrm 20}$

or, $\dfrac{240,141}{167,000}$ = $(1+\dfrac{\textrm r}{100})^{\textrm 20}$

Or , 1.437 = $(1+\dfrac{\textrm r}{100})^{\textrm 20}$

Or, $(1.437)^{\frac{1}{20}}$ = $(1+\dfrac{r}{100})$

or, 1.018 = $(1+\dfrac{r}{100})$

Or, $\dfrac{r}{100}$ = 1.018 - 1

Or, $\dfrac{r}{100}$ = 0.018

∴ r = 0.018 × 100

i.e r = 1.8

So, The rate of interest applied = r = 1.8 %

Hence, The Annual rate of interest for the mortgage is 1.8% Answer

8 0

3 years ago

Solve 2x + 5y = 20; 3x - 10y = 37 by elimination. How do you do this? Thank-you!

mr Goodwill [35]

$\left\{\begin{array}{ccc}2x+5y=20&\text{multiply both sides by 2}\\3x-10y=37\end{array}\right\\\\\underline{+\left\{\begin{array}{ccc}4x+10y=40\\3x-10y=37\end{array}\right}\qquad\text{add both sides of the equations}\\.\qquad7x=77\qquad\text{divide both sides by 7}\\.\qquad\boxed{x=11}\\\\\text{Put the value of x to the first equation:}\\\\2(11)+5y=20\\\\22+5y=20\qquad\text{subtract 22 from both sides}\\\\5y=-2\qquad\text{divide both sides by 5}\\\\\boxed{y=-\dfrac{2}{5}}\\\\Answer:\ \boxed{x=11\ and\ y=-\dfrac{2}{5}}$