<span>So you have composed two functions,
</span><span>h(x)=sin(x) and g(x)=arctan(x)</span>
<span>→f=h∘g</span><span>
meaning
</span><span>f(x)=h(g(x))</span>
<span>g:R→<span>[<span>−1;1</span>]</span></span>
<span>h:R→[−<span>π2</span>;<span>π2</span>]</span><span>
And since
</span><span>[−1;1]∈R→f is defined ∀x∈R</span><span>
And since arctan(x) is strictly increasing and continuous in [-1;1] ,
</span><span>h(g(]−∞;∞[))=h([−1;1])=[arctan(−1);arctan(1)]</span><span>
Meaning
</span><span>f:R→[arctan(−1);arctan(1)]=[−<span>π4</span>;<span>π4</span>]</span><span>
so there's your domain</span>
Answer:
36.72
Step-by-step explanation:
Take 60% of 61.20. That is the markup.
60% * 61.20 = 60/100 * 61.2 = 3672/100 = 36.72
The markup is 36.72
Answer:
r = 9
Step-by-step explanation:
cross multiply
9 * r = 81
9r = 81
divide both sides by 9
r= 81/9
r = 9
V = L * W * H
V = 4 * 4 * 8
V = 16 * 8
V = 128 cubic ft
Answer:
The answer is option A) X + 2
Step-by-step explanation:
Any polynomial of order n can be expressed in terms of their roots in factors of the form
(x-a)(x-b)(x-c)(x-d)....... = 0
Where a,b,c,d,... are the roots of the polynomial
In the example shown
(x+2) = (x-(-2))
And -2 happens to be the root of the polynomial in question
